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3 years ago

What is 241,639 rounded to the nearest thousand?

Mathematics

1 answer:

stich3 [128]3 years ago

3 0

Answer:

242,000

Step-by-step explanation:

Since the 6 in the hundreds place is greater than 5, you round up.

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Solve. −8.5d ≥ 20 d ≤ –170 d ≥ –170

saw5 [17]

Answer:

$\rm =>D \leqslant 2.352941$

Step-by-step explanation:

−8.5d ≥ 20

Divide both sides by -8.5:

$=> \cfrac {- 8.5 \: d}{ - 8.5} \ \geqslant \cfrac{20}{ - 8.5}$

$\rm=>d \leqslant 2.352941$

This is the answer.

3 0

2 years ago

Multiply the binomials: (x + 3y) (3x - 2y)

4vir4ik [10]

multiply the binomials:

(x + 3y) (3x - 2y)

Answer:

Simplify the expression:

3x^2+7xy−6y^2

Steps:

3x·2+7xy-6y·2

Multiply the numbers: 3·2=6

=6x+7xy-6·2y

Multiply the numbers: 6·2=12

=6x+7xy-12y

7 0

3 years ago

Attempted Solution:3x+27=6x in 2 cases

Alekssandra [29.7K]

Answer:

Step-by-step explanation:

You take 3x and subtract it from both sides.

3x-3x+27=6x-3x

You now should have 27=3x. Divide 3 from 27 to get 9 as your total.

4 0

3 years ago

An environmentalist wants to find out the fraction of oil tankers that have spills each month. Suppose a sample of 836 tankers i

Alexxandr [17]

Answer:

The 99% confidence interval for the population proportion of oil tankers that have spills each month.

(0.6489 , 0.7311)

Step-by-step explanation:

Step(i):-

Given sample size 'n' = 836

Suppose a sample of 836 tankers is drawn. Of these ships, 577 did not have spills.

sample proportion

$p^{-} = \frac{x}{n} = \frac{577}{836} = 0.690$

The 99% confidence interval for the population proportion is determined by

$(p^{-} - Z_{0.01} \sqrt{\frac{p(1-p)}{n} } , p^{-} + Z_{0.01} \sqrt{\frac{p(1-p)}{n} })$

Step(ii):-

The Z- value = 2.576

$(0.690 - 2.576 \sqrt{\frac{0.690(1-0.690)}{836} } , 0.690 + 2.576 \sqrt{\frac{0.690(1-0.690)}{836} })$

On calculation , we get

(0.690 - 0.0411 , 0.690 + 0.0411)

(0.6489 , 0.7311)

Final answer:-

The 99% confidence interval for the population proportion of oil tankers that have spills each month.

(0.6489 , 0.7311)

8 0

4 years ago

You choose 3 bananas from a group of 9. In how many ways can this be done?

alexandr1967 [171]

Assuming the order of selection doesn't matter:

$\displaystyle \binom{9}{3}=\dfrac{9!}{3!6!}=\dfrac{7\cdot8\cdot9}{2\cdot3}=84$

6 0

4 years ago