Using linear combination method to solve the system of equations 3x - 8y = 7 and x + 2y = -7 is (x, y) = (-3, -2)
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Given that, a system of equations are:
3x – 8y = 7 ⇒ (1) and x + 2y = - 7 ⇒ (2)
We have to solve the system of equations using linear combination method and find their solution.
Linear combination is the process of adding two algebraic equations so that one of the variables is eliminated. Addition or subtraction can be used to perform a linear combination.
Now, let us multiply equation (2) with 4 so that y coefficients will be equal numerically.
4x + 8y = -28 ⇒ (3)
Now, add (1) and (3)
3x – 8y = 7
4x + 8y = - 28
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7x + 0 = - 21
7x = -21
x = - 3
Now, substitute "x" value in (2)
(2) ⇒ -3 + 2y = - 7
2y = 3 – 7
2y = - 4
y = -2
Hence, the solution for the given two system of equations is (-3, -2)
The normal vectors to the two planes are (3, 3, 2) and (2, -3, 2). The cross product of these will be the direction vector of the line of intersection, (12, -2, -15).
Using x=0, we can find a point on this line by solving the simultaneous equations that remain:
... 3y +2z = -2
... -3y +2z = 2
Adding these, we get
... 4z = 0
... z = 0
so the point we're looking for is (x, y, z) = (0, -2/3, 0). This gives rise to the parametric equations ...
- x = 12t
- y = -2/3 -2t
- z = -15t
By letting t=2/3, we can find a point on the line that has integer coefficients. That will be (x, y, z) = (8, -2, -10).
Then our parametric equations can be written as
- x = 8 +12t
- y = -2 -2t
- z = -10 -15t
Let a and b be odd number.
Because they are odd, by definition:
a = 2n + 1
b = 2m + 1
If we add them up:
a + b = 2n + 1 + 2m + 1
= 2n + 2m + 2
= 2(n + m + 2)
= 2k where k = n + m + 2
therefore a + b is always even.
11x + 4y
combine like terms together (add 6x and 5x)
Answer:
From the given statement the value of b is calculate as 8
Step-by-step explanation:
The given statement is
+ 1 = 3
This is a form of simple equation
= 3 - 1
= 2
Or, b = 2 × 4
I.e b = 8
Hence from the given statement the value of b is calculate as 8 Answer
