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elena55 [62]
3 years ago
10

What are the factor pairs for 100?

Mathematics
1 answer:
Lana71 [14]3 years ago
6 0
1,2,4,5,10,20,25,50,100
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Write the equation of the line perpendicular to y = -3/4x that passes through the point (3,-8)
arlik [135]

Answer:

y = \frac{4}{3} x - 12

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = - \frac{3}{4} x ← is in slope- intercept form

with slope m = - \frac{3}{4} , c = 0

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{-\frac{3}{4} } = \frac{4}{3} , then

y = \frac{4}{3} x + c ← is the partial equation

To find c substitute (3, - 8) into the partial equation

- 8 = 4 + c ⇒ c = - 8 - 4 = - 12

y = \frac{4}{3} x - 12 ← equation of perpendicular line

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3 years ago
If the area of the blue square is 25 in2 and the area of the green square is 15 points
galben [10]

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Step-by-step explanation:

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3 years ago
What is the slope of this line
Troyanec [42]
The slope of this line is m=0









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3 years ago
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A set of data has a normal distribution with a mean of 46 and a standard deviation of 7. Find the percent of data within the fol
kvasek [131]

Answer:

50%

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1 year ago
Calculus: Help ASAP
wariber [46]
\bf \displaystyle \int~\cfrac{sec^2(x)}{\sqrt{1+tan(x)}}\cdot  dx\\\\
-------------------------------\\\\
u=1+tan(x)\implies \cfrac{du}{dx}=sec^2(x)\implies \cfrac{du}{sec^2(x)}=dx\\\\
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\displaystyle \int~\cfrac{\underline{sec^2(x)}}{\sqrt{u}}\cdot\cfrac{du}{\underline{sec^2(x)}}\implies \int~\cfrac{1}{\sqrt{u}}\cdot du\implies \int~u^{-\frac{1}{2}}\cdot du
\\\\\\
2u^{\frac{1}{2}}\implies 2\sqrt{1+tan(x)}+C
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3 years ago
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