x=1, y=2
Solve the following system:
{y = 5 - 3 x5 x - 4 y = -3
Substitute y = 5 - 3 x into the second equation:
{y = 5 - 3 x5 x - 4 (5 - 3 x) = -3
5 x - 4 (5 - 3 x) = (12 x - 20) + 5 x = 17 x - 20:{y = 5 - 3 x17 x - 20 = -3
In the second equation, look to solve for x:{y = 5 - 3 x17 x - 20 = -3
Add 20 to both sides:{y = 5 - 3 x17 x = 17
Divide both sides by 17:{y = 5 - 3 xx = 1
Substitute x = 1 into the first equation:{y = 2x = 1
Collect results in alphabetical order:Answer: {x = 1 y = 2
Answer:
10(3)^x
Step-by-step explanation:
The function contains the points (2,90) and (4,810). Use the general form y=abx to write two equations:
90=ab^2 and 810=ab^4
Solve each equation for a:
a=90/b^2 and a=810/b^4
Since a=a, set the other sides of the equations equal and solve for b.
90/b2=810/b4
Cross multiply, then divide and simplify as follows:
90b^4=810b^2
b^4/b^2=810/90
b^2=90
b^3
Now, use the value of b and the point (2,90) to find the value of a.
90=a(3^2)
a=10
So, substitute answers in original equation for a final answer of f(x)=10(3)^x.
Answer:
Step-by-step explanation:
7 / 54 * 27/35 =
1/2 * 1/5 =
1/10 <===
Answer:
<h2>D</h2>
Step-by-step explanation:
If pair of ratios does form a true proportion then:



Answer: 
Step-by-step explanation:
The volume of a cube can be found with this formula:

Where "s" is the lenght of any edge of the cube.
The formula for calculate the volume of a rectangular prism is:

Where "l" is the lenght, "w" is the width and "h" is the height.
We need to find the volume of a cube box:

To find the volume of the shipping box, first we must convert the mixed number to an improper fraction:

Then the volume of the shipping box is:

Now, in order to find the number of cube boxes can Haley fits into a shipping box, you must divide the the volume of the shipping box by the volume of one cube. This is:
