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2 years ago

Please help with this magic square

Mathematics

1 answer:

IrinaVladis [17]2 years ago

3 0

Answer:

-0.06 left-middle

0.28 right-middle

0.03 right-top

0.1 middle-top

0.12 middle-bottom

Step-by-step explanation:

column-row

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Robert is going to invest $640 and leave it in an account for 20 years. Assuming the interest is compounded quarterly, what inte

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Answer:

Interest rate ≈ 3.48%

Step-by-step explanation:

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2 years ago

How many gold medals have been awarded for the 1500-meter race from 1896 - 2000 ?

Nataly [62]

Answer:

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Step-by-step explanation:

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11 months ago

Read 2 more answers

Slips of paper numbered 1 to 15 are placed in a box. A slip of paper is drawn at random. What is the probability that the number

monitta

Given:

Slips of paper numbered 1 to 15 are placed in a box.

To find:

The probability that the number picked is either a multiple of 5 or an odd number.

Solution:

We have,

Total outcomes = 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15

No. of total outcomes = 15

Multiple of 5 are 5, 10, 15.

Odd numbers are 1, 3, 5, 7, 9, 11, 13, 15.

Number that are either a multiple of 5 or an odd number are 1, 3, 5, 7, 9, 10, 11, 13, 15.

No. of favorable outcomes = 9

We know that,

$\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}$

$\text{Probability}=\dfrac{9}{15}$

$\text{Probability}=\dfrac{3}{5}$

$\text{Probability}=0.6$

Therefore, the probability that the number picked is either a multiple of 5 or an odd number is 0.6.

8 0

2 years ago

Hello please help me out

Doss [256]

Answer:

7. -10/x

8.0

Step-by-step explanation:

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2 years ago

Create a matrix that is equal to F+G. The first matrix below is named F and the second matrix below is named G. Name the new mat

likoan [24]

F+G:

$F+G=\begin{bmatrix}{-1.8} & {-8.6} & {} \\ {2.85} & {-1.4} & {} \\ {-1.8} & {5.1} & {}\end{bmatrix}+\begin{bmatrix}{1.32} & {-1.9} & {} \\ {2.25} & {0.0} & {} \\ {-6.2} & {1.4} & {}\end{bmatrix}$

Then, add the elements that occupy the same position:

$H=\begin{bmatrix}{-1.8+1.32} & {-8.6+(-1.9)} & {} \\ {2.85+2.25} & {-1.4+0.0} & {} \\ {-1.8+(-6.2)} & {5.1+1.4} & {}\end{bmatrix}$

Solve

$H=\begin{bmatrix}{-0.48} & {-10.5} & {} \\ {5.1} & {-1.4} & {} \\ {-8} & {6.5} & {}\end{bmatrix}$

So, we find the element at address h31:

$H=\begin{bmatrix}{h11} & {h12} & {} \\ {h21} & {h22} & {} \\ {h31} & {h32} & {}\end{bmatrix}$

In this case, position h31 is - 8.0

8 0

11 months ago