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Genrish500 [490]
3 years ago
14

John can run 7 miles in 45 minutes. What is John's rate of speed in miles per hour?

Mathematics
1 answer:
kolbaska11 [484]3 years ago
6 0

Answer:

ur answer 6 3/7 miles per hour

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Can anyone help me please? Also explain if you can. Thank you :)
djverab [1.8K]
The answer is 6/9 or 2/3 because 2X2X2=8 and 9X9X9=729......it equals 8/729 






3 0
3 years ago
Suppose that 70% of the orders on a particular website are shipped to the person who is making the order and the remaining 30% a
Lera25 [3.4K]

Answer:

0.18 ; 0.1875 ; No

Step-by-step explanation:

Let:

Person making the order = P

Other person = O

Gift wrapping = w

P(p) = 0.7 ; P(O) = 0.3 ; p(w|O) = 0.60 ; P(w|P) = 0.10

What is the probability that a randomly selected order will be a gift wrapped and sent to a person other than the person making the order?

Using the relation :

P(W|O) = P(WnO) / P(O)

P(WnO) = P(W|O) * P(O)

P(WnO) = 0.60 * 0.3 = 0.18

b. What is the probability that a randomly selected order will be gift wrapped?

P(W) = P(W|O) * P(O) + P(W|P) * P(P)

P(W) = (0.60 * 0.3) + (0.1 * 0.7)

P(W) = 0.18 + 0.07

P(W) = 0.1875

c. Is gift wrapping independent of the destination of the gifts? Justify your response statistically

No.

For independent events the occurrence of A does not impact the occurrence if the other.

4 0
3 years ago
What’s the correct answer for this question?
Korvikt [17]

Answer:

1)

Volume of pyramid = 1/3(Ab)(h)

Where Ab is the area of base, h is height

Volume of cone = 1/3(Ab)(h)

a) Their formula for finding volume is same. Also, their painting heads are same.

b) Pyramids have a tetragonal base while cones have a polygonal base

2) Pyramids

Volume of cone = (1/3) πr²h

Since Area of a circle = πr²

So

Volume of pyramid = (1/3)(A)(h)

So we can use the formula of a circle in cone's formula

6 0
3 years ago
Read 2 more answers
In triangle MNO shown below, segment NP is an altitude:
Effectus [21]

Answer:  C. Definition of an Altitude

Step-by-step explanation:

Given: In triangle MNO shown below, segment NP is an altitude from the right angle.

Let ∠MNP=x

Then ∠PNO=90°-x

Therefore in triangle MNO,

∠MPN=∠NPO =90°  [by definition of Altitude]

[Definition of altitude : A line which passes through a vertex of a triangle, and joins the opposite side forming right angles. ]

Now using angle sum property in ΔMNP

∠MNP+∠MPN+∠PMN=180°

⇒x+90°+∠PMN=180°

⇒∠PMN=180°-90°-x

⇒∠PMN=90°-x

Now, in ΔMNO and ΔPNO

∠PMN=∠PNO=90°-x

and ∠MPN=∠NPO =90°  [by definition of altitude]

Therefore by AA similarity postulate, we have

ΔMNO ≈ ΔPNO

5 0
3 years ago
Solve the following question algebraically. SOMEONE PLEASE HELP ME! ILL MARK THE BRAINLIEST ANSWER!!I’VE TRIED TO FIGURE IT OUT
Delicious77 [7]

Solve for x. Isolate the x. Note the equal sign. What you do to one side, you do to the other. Do the opposite of PEMDAS.

First, multiply 3 to both sides

6(3) = ((x + 2)/3)(3)

18 = x + 2

Finally, isolate the x. Subtract 2 from both sides

18 (-2) = x + 2 (-2)

x = 18 - 2

x = 16

16 is your answer for x

hope this helps

8 0
3 years ago
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