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3 years ago

Evaluate the expression 2x + 2 starting at 5, ending at 20, and stepping by 5. You

Mathematics

1 answer:

kiruha [24]3 years ago

6 0

Answer:

X _____Y

5_____12

10____22

15____32

20___ 42

Step-by-step explanation:

Given the expression ; 2x + 2 with X starting at 5 and ending at 20;

X _____Y

5___ 2(5) + 2 = 10 + 2 = 12

10__ 2(10) + 2 = 20 + 2 = 22

15 __ 2(15) + 2 = 30 + 2 = 32

20__ 2(20) + 2 = 40 + 2 = 42

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ella [17]

Hey there! I'm happy to help!

We have $100.75 to spend.

Each spool costs $3, and we have 24 spools.

3×24=72

Each glue costs $1 and we have 7 packages of glue.

7×1=7

We add up these expenses.

72+7=79

And we subtract from our total amount.

100.75-79=21.75

So, Joanna has $21.75 left after buying these things.

Have a wonderful day and keep on learning! :D

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2 years ago

Read 2 more answers

Resolve (5x+4) /( (x-4)( x+2))

vazorg [7]

Answer:

Step-by-step explanation:

Hello!

(5x+4) /( (x-4)( x+2))

(5x+4)/ (x² +2x -4x -8)=

(5x+4) /( x²-2x -8)

7 0

3 years ago

Pleas help me with 16. The first best answer gets brainlist.

Butoxors [25]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

How many computers must the AB Computer Company sell to break even? Let x be the number of computers.

Eduardwww [97]

Answer:

The Company AB must sell 116 computers to break even

Step-by-step explanation:

we have

$R(x)=1.5x$ -----> equation A

$C(x)=145+\frac{1}{4}x$ ----> equation B

where

C is the cost function

R is the revenue function

x is the number of computers sold

we know that

Break even is when the cost is equal to the revenue

equate equation A and equation B

$1.5x=145+\frac{1}{4}x$

Solve for x

subtract 1/4x both sides

$1.5x-\frac{1}{4}x=145$

$1.5x-0.25x=145$

$1.25x=145$

Divide by 1.25 both sides

$x=116$

therefore

The Company AB must sell 116 computers to break even

7 0

3 years ago

Find the constant of variation k for the inverse variation. Then write an equation for the inverse variation. Y=4.5 when x = 3

Nookie1986 [14]

$\bf \qquad \qquad \textit{inverse proportional variation}\\\\
\textit{\underline{y} varies inversely with \underline{x}}\qquad \qquad y=\cfrac{k}{x}\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
\textit{we also know that }
\begin{cases}
y=4.5\\
x=3
\end{cases}\implies 4.5=\cfrac{k}{3}\implies 4.5(3)=k
\\\\\\
13.5=k\qquad therefore\qquad \boxed{y=\cfrac{13.5}{x}}$

8 0

2 years ago