9514 1404 393
Answer:
"complete the square" to put in vertex form
Step-by-step explanation:
It may be helpful to consider the square of a binomial:
(x +a)² = x² +2ax +a²
The expression x² +x +1 is in the standard form of the expression on the right above. Comparing the coefficients of x, we see ...
2a = 1
a = 1/2
That means we can write ...
(x +1/2)² = x² +x +1/4
But we need x² +x +1, so we need to add 3/4 to the binomial square in order to make the expressions equal:
_____
Another way to consider this is ...
x² +bx +c
= x² +2(b/2)x +(b/2)² +c -(b/2)² . . . . . . rewrite bx, add and subtract (b/2)²*
= (x +b/2)² +(c -(b/2)²)
for b=1, c=1, this becomes ...
x² +x +1 = (x +1/2)² +(1 -(1/2)²)
= (x +1/2)² +3/4
_____
* This process, "rewrite bx, add and subtract (b/2)²," is called "completing the square"—especially when written as (x-h)² +k, a parabola with vertex (h, k).
General Idea:
W
hen we are given a point P(x, y) centered at origin with a scale factor of k, then the dilated point will be given by P' (kx, ky)
When
, then P' is enlargement of P
When 
, then P' is reduction of P
Applying the concept:
In the diagram given A'B'C' is enlargement of ABC. So the correct option will be option A. 
, enlargement
Answer:
domain = {x|xER}
range = {y|y≥0,yER}
Step-by-step explanation:
|x| means the absolute value which in this case is the distance from 0. On a graph this function would look like a v and would mean it would have infinite x-values since it is opening upwards in both directions.
For the range the vertex of this function is (0,0), if the x-coordinate were 0 the y-coordinate would be 0 because the absolute distance from 0 is 0. for another x-coordinate say -2 the absolute distance from 0 is 2 meaning the y-value is 0 since y=|x|, making the coordinate (-2,2) meaning the range is every y value must be above 0 since there is no way for the y-value to be negative
Answer:
hey
Step-by-step explanation:
idk
Answer: There equal
Step-by-step explanation:
multiply by 10
