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3 years ago

5

4(2x – 5) = 4 Part A: How many solutions does this equation have? (4 points) Part B: What are the solutions to this equation? Sh

ow your work. (6 points)

1 answer:

Gnom [1K]3 years ago

7 0

A. one solution
B 4(2x-5) = 4
2x-5 = 1
2x = 6
x=3

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Answer:

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Step-by-step explanation:

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2 years ago

A cylinder has a radius of 3 feet and a height of 7 feet. Which of the following can be used to calculate the volume of a cone t

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Answer:

$(3.14)(3)(7)$

Step-by-step explanation:

we know that

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$V=\frac{1}{3}\pi r^{2} h$

we have that the radius and the height of the cone will be equal to the radius and the height of the cylinder

so

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3 years ago

−5x+2y=9<br> y=7x<br> what is x and y

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Answer:

{x,y}={1,7}

Step-by-step explanation:

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2 years ago

Elasticity is also called

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Another word for elasticity is also called D: responsiveness

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3 years ago

Differentiate x^2 e^x logx

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Product rule:

$\dfrac{\mathrm d}{\mathrm dx}(x^2e^x\log x)$

$=\dfrac{\mathrm d(x^2)}{\mathrm dx}e^x\log x+x^2\dfrac{\mathrm d(e^x)}{\mathrm dx}\log x+x^2e^x\dfrac{\mathrm d(\log x)}{\mathrm dx}$

Power rule:

$\dfrac{\mathrm d(x^2)}{\mathrm dx}=2x$

The exponential function is its own derivative:

$\dfrac{\mathrm d(e^x)}{\mathrm dx}=e^x$

Assuming the base of $\log x$ is $e$ , its derivative is

$\dfrac{\mathrm d(\log x)}{\mathrm dx}=\dfrac1x$

But if you mean a logarithm of arbitrary base $b$ , we have

$y=\log_bx\implies x=b^y=e^{y\ln b}\implies1=e^{y\ln b}\ln b\dfrac{\mathrm dy}{\mathrm dx}$

$\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{e^{-y\ln b}}{\ln b}=\dfrac1{b^y\ln b}$

$\implies\dfrac{\mathrm d(\log_bx)}{\mathrm dx}=\dfrac1{x\ln b}$

So we end up with

$2xe^x\log x+x^2e^x\log x+\dfrac{x^2e^x}x$

$=xe^x(2\log x+x\log x+1)$

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3 years ago