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Answer:
the guarantee period should be less than 136010 miles
Step-by-step explanation:
From the given information;
Let consider Y to be the life of a car engine
with a mean μ = 170000
and a standard deviation σ = 16500
The objective is to determine what should be the guarantee period T if the company wants less than 2% of the engines to fail.
i.e
P(Y < T ) < 0.02
For the variable of z ; we have:
Now;
From Z table ;
At P(Z < -2.06) ≅ 0.0197 which is close to 0.02
Thus; the guarantee period should be less than 136010 miles
Answer:
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Step-by-step explanation:
4.
Solve for either of the variable. I solved for c because it looked easier.
Set c = 0 to solve for the x-intercept so that you can graph it. c is just your y-value in this case and m is your x-value.
I got m=90 which means it crosses the x-axis at 90. I also know it cross the y-axis at 90 because c = 90 - m is in the form of slope-intercept formula. The 90 in there is the y-intercept.
The sign is a > so it's a dotted line shaded above the graph.
5.
Same process as part 4. Set c=0 to find the x-intercept. I got m=100 which means it cross the x-axis at 100.
The y-intercept is in the equation itself c = 80 - 4/5m. The y-intercept is 80.
The sign is a ≥ so it's a solid line shaded above the graph.
