Answer:
1-chloro-1-methylcyclohexane
Explanation:
The hydrocarbons with one double bond are called alkenes and are named with the suffix "ene". The alkenes, such as 1-methylcyclohexene, react better in an addition reaction. The double bond will be broken, and the substitutes will be placed at them.
In the reaction with HCl, H and Cl will be added to the carbons of the broken bond. The major product is formed when H is put at the carbon less substituted. Thus, the product will be the one given below, 1-chloro-1-methylcyclohexane.
Answer:
mol·L⁻¹·s⁻¹
Explanation:
In the case of a <em>zero-order reaction</em>, the reaction rate does not change with the decrease or increase in the concentrations of the reactants:
And because the rate must have units of mol·L⁻¹·s⁻¹, then the rate constant <em>k</em> must also have units of mol·L⁻¹·s⁻¹.
<u>An element is the simplest form of a substance. ... An atom is the part of an element. A particular element is composed of only one type of atom. Atoms are further composed of subatomic particles called electrons, protons and neutrons.</u>
Answer:
0.717 M LiOH
Explanation:
(Step 1)
Calculate the moles of H₃PO₄ using the molarity equation.
29.15 mL / 1,000 = 0.02915 L
Molarity = moles / volume (L)
0.205 M = moles / 0.02915 L
0.00598 = moles
(Step 2)
Convert moles H₃PO₄ to moles LiOH using the mole-to-mole ratio from reaction coefficients.
1 H₃PO₄ + 3 LiOH -----> Li₃PO₄ + 3 H₂O
^ ^
0.00598 moles H₃PO₄ 3 moles LiOH
------------------------------------ x -------------------------- = 0.0179 moles LiOH
1 mole H₃PO₄
(Step 3)
Calculate the molarity of LiOH using the molarity equation.
25.0 mL / 1,000 = 0.0250 L
Molarity = moles / volume (L)
Molarity = 0.0179 moles / 0.0250 L
Molarity = 0.717 M
