Question

An elastic cord can be stretched to its elastic limit by a load of 2N.If a 35cm length of the cord is extended 0.6cm by a force of 0.5N,what will be the length of the cord when the stretching force is 2.5N​

Answer 1

Explanation:

$from \: hookes \: law \\ F = k.e \\ but \: e = 0.6 \: cm \\ 2 = k \times 0.6 \\ k = 3.33 \\ when \:F \: is \: 2.5 \\ 2.5 = 3.33 \times e {}^{.} \\ {e}^{. } = 0.75 \: cm \\ new \: length = 35 - {e}^{.} \\ = 35 - 0.75 \\ = 34.25 \: cm$