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3 years ago

1.) Fluorite has a glassy luster and a white streak. It's an inorganic solid with a chemical formula of CaF2 CaF2

Chemistry

2 answers:

Nesterboy [21]3 years ago

8 0

Answer:

D. All of the above

Explanation:

Musya8 [376]3 years ago

6 0

Answer:

D. All of the above

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Assume that your electrical power company gets its energy from a hydroelectric dam. Outline all of the energy changes that occur

Rina8888 [55]

Answer:

See explanation.

Explanation:

This isn't chemistry. Its physics. Kinetic energy (water) to electric energy (dam) as the hydroelectric dam works. Then, as the current travels from the plant to your crib, electric energy to heat energy (wire resistance). Then when you are using the dryer electric energy to heat energy (hot air) and sound energy (air particles vibrate due to the heat energy).

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2 years ago

Sulphur burnt in oxygen forms sulphur dioxide. Calculate the heat given out when 1.6g of sulphur is burnt.

adell [148]

Answer:

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Explanation:

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3 years ago

The primary gas in a volocano is?

stiv31 [10]

Answer:

By far the most abundant volcanic gas is water vapor, which is harmless. However, significant amounts of carbon dioxide, sulfur dioxide, hydrogen sulfide and hydrogen halides can also be emitted from volcanoes

Explanation:

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3 years ago

Read 2 more answers

The mass of an object is 216 g and the volume is 24 ml. What is the density

Stells [14]

Answer:

Explanation:

The density of a substance can be found by using the formula

$density = \frac{mass}{volume} \\$

From the question we have

$density = \frac{216}{24} \\$

We have the final answer as

Hope this helps you

6 0

2 years ago

The Pfund series of lines in the emission spectrum of hydrogen corresponds to transitions from higher excited states to the n =

lys-0071 [83]

Answer:

$\large \boxed{\text{4650 nm}}$

Explanation:

The second line in the Pfund series corresponds to a transition from n = 7 to n = 5.

To calculate the wavelength of the transition, we can use the Rydberg equation:

$\dfrac{1}{\lambda} = R_{H}\left ( \dfrac{1 }{n_{1}^{2}} - \dfrac{1 }{n_{2}^{2}} \right )$

where

$R_{H} = 1.097 \times 10^{7} \text{ m}^{-1}$

If n₁ = 5 and n₂ = 7

$\begin{array}{rcl}\dfrac{1}{\lambda} & = & 1.097 \times 10^{7} \text{ m}^{-1}\left ( \dfrac{1 }{5^{2}} - \dfrac{1 }{7^{2}} \right )\\\\ & = & 1.097 \times 10^{7} \text{ m}^{-1}\left ( \dfrac{1 }{25} - \dfrac{1 }{49} \right )\\\\ & = & 1.097 \times 10^{7} \text{ m}^{-1}\left ( \dfrac{49 - 25 }{49 \times25}\right )\\\\& = & 1.097 \times 10^{7} \text{ m}^{-1}\left ( \dfrac{24 }{1225}\right )\\\\ & = & 2.149 \times 10^{7}\text{ m}^{-1}\\\end{array}\\$

$\begin{array}{rcl}\lambda & = & \dfrac{1}{2.149 \times 10^{7}\text{ m}^{-1}}\\\\ & = & 4.65 \times 10^{-6} \text{ m}\\ & = & \mathbf{4650} \textbf{ nm}\\\end{array}\\\text{The wavelength of the line is $\large \boxed{\textbf{4650 nm}}$, which is in the $\textbf{infrared region}$}.$

8 0

3 years ago