Ask question

Ask question

All categories

3 years ago

12

What is one benefit of using a chemical formula?

1 answer:

MrRa [10]3 years ago

8 0

The following are the benefits of chemical formula:
1. we can know the images of the compound.
2. adjusted condition can be known.
3. heading of the response.
4. we can know the no. of reactants and no. of items associated with the compound response.
5. no. of iotas display in a compound can be known.

You might be interested in

Many medical devices are designed using the electromagnetic spectrum. Which type of electromagnetic wave has enough energy to ki

tresset_1 [31]

Gamma rays because the kill every living cell and they have the shortest waves that are dangerous

4 0

3 years ago

Cart A has a mass of 24 kg and is being pulled with a force of 32 N. Cart B has a mass of

horsena [70]

Cart b because it has greater force and higher mass

4 0

3 years ago

Consider the reaction below. At 500 K, the reaction is at equilibrium with the following concentrations. [PCI5]= 0.0095 M [PCI3]

Dmitriy789 [7]

Answer: The equilibrium constant for the given reaction is 0.0421.

Explanation:

$PCl_5\rightleftharpoons PCl_3+Cl_2$

Concentration of $[PCl_5]$ = 0.0095 M

Concentration of $[PCl_3]$ = 0.020 M

Concentration of $[Cl_2]$ = 0.020 M

The expression of the equilibrium constant is given as:

$K_c=\frac{[PCl_3][Cl_2]}{[PCl_5]}=\frac{0.020 M\times 0.020 M}{0.0095 M}$

$K_c=0.0421$ (An equilibrium constant is an unit less constant)

The equilibrium constant for the given reaction is 0.0421.

6 0

3 years ago

Read 2 more answers

Glucose (C6H12O6) can be fermented to yield ethanol (CH3CH2OH) and carbon dioxide (CO2). C6H12O6⟶2CH3CH2OH+2CO2 The molar mass o

jekas [21]

Answer:

The % yield is 74.45 %

Explanation:

<u>Step 1:</u> The balanced equation

C6H12O6⟶2CH3CH2OH+2CO2

<u>Step 2</u>: Data given

Molar mass glucose = 180.15 g/mol

Molar mass of ethanol = 46.08 g/mol

Molar mass of carbon dioxide = 44.01 g/mol

Mass of glucose = 61.5 grams

Mass of ethanol = 23.4 grams

<u>Step 3:</u> Calculate moles of glucose

Moles glucose = Mass glucose / Molar mass of glucose

Moles glucose = 61.5 grams / 180.15 g/mol

Moles glucose = 0.341 moles

<u>Step 4:</u> Calculate moles of ethanol

1 mole of glucose consumed, produces 2 moles of ethanol and 2 moles of CO2

0.341 moles of glucose, will produce 2*0.341 = 0.682 moles of ethanol

<u>Step 5:</u> Calculate mass of ethanol

Mass ethanol = moles ethanol * Molar mass ethanol

Mass ethanol = 0.682 moles * 46.08 g/mol

Mass ethanol = 31.43 grams = theoretical mass

<u>Step 6:</u> Calculate % yield

% yield = actual mass / theoretical mass

% yield = (23.4 grams / 31.43 grams) * 100%

% yield = 74.45 %

The % yield is 74.45 %

7 0

3 years ago

Which of the following are quantized? A) canned soup from the grocery store b) the weight of jelly beans c) elevation of a perso

alisha [4.7K]

Both <span>b) the weight of jelly beans and c) elevation of a person on a ramp</span>

6 0

3 years ago