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4 years ago

Write an equation of the direct variation that includes the point (5,1)

Mathematics

2 answers:

V125BC [204]4 years ago

5 0

Answer:

y = 5x

Step-by-step explanation:

X=5 and Y=1

Direct variation can be represented by the equation y=kx.

Therefore,

1 = k(5)

5 = k

Now you use, k = 5 to write the direct variation equation.

Which gives you the answer y = 5x

8090 [49]4 years ago

4 0

Answer:

y = 1/5k

Step-by-step explanation:

y = kx

1= k(5)

1/5 = l

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Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the gi

dimulka [17.4K]

a parallel line to that equation will have the same exact slope, so

$\bf y=\stackrel{\stackrel{m}{\downarrow }}{-3}x+5\impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

then we're really looking for the equation of a line whose slope is -3, and runs through (-5,-8)

$\bf (\stackrel{x_1}{-5}~,~\stackrel{y_1}{-8})~\hspace{10em} slope = m\implies -3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-(-8)=-3[x-(-5)] \\\\\\ y+8=-3(x+5)\implies y+8=-3x-15\implies y=-3x-23$

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3 years ago

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What type of bar graph that display frequency of data

alexandr1967 [171]

Answer:

<>"similar to a histogram in that it is a graph depicting the frequency of continuous data. however, a frequency polygon is in line form instead of bar form. A graphic technique used to display the frequency distribution of continuous data (interval or ratio data) as either numbers or percentages in a series of bars."<>

Step-by-step explanation:

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4 years ago

I'm Timed

Tju [1.3M]

It would be C. Because PEMDAS. Division goes first in this equation. So it’d be 15 divided by 3 plus 6

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3 years ago

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The waiting times at a certain bank are normally distributed with a mean waiting time of 3.7 minutes and a standard deviation of

muminat

Answer:

From the given options we can say the correct answer is d.) 6.3

Step-by-step explanation:

The waiting times at the bank are given to be normally distributed.

The mean of the waiting time is given as = 3.7 minutes

The given standard deviation is = 1.4 minutes

It is required to find the waiting time at the 97th percentile.

So we are required to find the time which can be said to be the waiting time which occurs with 97 % probability.

Let the time required be designated as y.

Therefore we can write p(X < y) = 0.97 (where 0.97 means the 97th percentile)

This is a left tailed test.

Using the formula from MSEXCEL to find y we get

y = NORMINV(0.97, 3.7, 1.4) = 6.333.

The other approach would to find the Z value corresponding to the probability value from the Z Table

The Z value for a probability of 0.97 gives us Z = 1.881 .

Therefore $\frac{y - 3.7}{1.4} = 1.881$ . Therefore y = (1.881 × 1.4) + 3.7 = 6.33

Therefore from the given options we can say the correct answer is d.) 6.3

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3 years ago

Which expression is equivalent to 12*12*12*12*12*12*12*12*12*12*12<br>

ELEN [110]

Answer:

$12^{11}$

Step-by-step explanation:

12 has the exponent of 11

12 is the base

^11 is the exponent

since 12 is multiplied by itself 11 times, so that means we will have the exponent of 11...

final answer: $12^{11}$

I hope this helps you :) ! let me know if I am incorrect or not

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3 years ago

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