Is force a vector, scalar, both, neither
2 answers:
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Answer: find the attached figure for a and b
Explanation:
A) The second figure depict electric field lines and equipotential lines for two equal but opposite charges. The equipotential lines can be drawn by making them perpendicular to the electric field lines. The potential is greatest (most positive) near the positive charge and least (most negative) near the negative charge.
B) The figure attached depicts an isolated point charge Q with its electric field lines in blue and equipotential lines in green. The potential is the same along each equipotential line, meaning that no work is required to move a charge anywhere along one of those lines. Work is needed to move a charge from one equipotential line to another. Equipotential lines are perpendicular to electric field lines in every case.
Please find the attached file for the figure
<h2>Answer:</h2>
<em>1.33 x 10⁻ ⁴ T outwards.</em>
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<h2>Explanation:</h2>The equation for the magnetic force (F) on a wire whose length is L and carrying a current I in a magnetic field (B) that is uniform is given by;
F = ILB sin θ ---------------------(i)
Where;
θ = angle between the direction of the current and that of the magnetic field.
From the question,
F = 4.0 × 10⁻² N
I = 12A
L = 25m
θ = 90°
<em>Substitute these values into equation(i) and solve as follows;</em>
4.0 × 10⁻² = 12 x 25 x B x sin 90°
4.0 × 10⁻² = 300 x B x 1
4.0 × 10⁻² = 300B
0.04 = 300B
B =
B = 0.000133
B = 1.33 x 10⁻ ⁴ T
To get the direction of the magnetic field, the right-hand rule is used.
If the right hand fingers are positioned in the correct order specified by the right hand rule, then it would be seen that the magnetic field is directed outwards.
Therefore, the magnitude and direction of the magnetic field at this location is <em>1.33 x 10⁻ ⁴ T outwards.</em>