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inessss [21]
3 years ago
15

Draw equipotential lines near the positive and negative charges below with dashed lines. b) Draw solid electric field lines base

d on the fact that they are perpendicular to the equipotential lines at every point. Include arrows on the electric field lines to indicate their direction (since they represent vectors at each location).

Physics
1 answer:
pychu [463]3 years ago
5 0

Answer: find the attached figure for a and b

Explanation:

A) The second figure depict electric field lines and equipotential lines for two equal but opposite charges. The equipotential lines can be drawn by making them perpendicular to the electric field lines. The potential is greatest (most positive) near the positive charge and least (most negative) near the negative charge.

B) The figure attached depicts an isolated point charge Q with its electric field lines in blue and equipotential lines in green. The potential is the same along each equipotential line, meaning that no work is required to move a charge anywhere along one of those lines. Work is needed to move a charge from one equipotential line to another. Equipotential lines are perpendicular to electric field lines in every case.

Please find the attached file for the figure

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To solve this problem we will apply Newton's second law. The second law says that mass by acceleration is equivalent to the Force exerted on a body. Mathematically this

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3 years ago
Describe a situation in your everyday life where you could use the scientific method. List all the steps of the scientific metho
emmainna [20.7K]

Yes, scientific method can be applied on many everyday activities to get a reasonable solution. Infact normally we are applying this method without having it in our knowledge that we are applying it.

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Experiment (testing of hypothesis by applying different methods of solving problem):

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Analyze the results of data and test another hypothesis

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8 0
4 years ago
Question number 11 how did we found the answer ?
BaLLatris [955]

Answer:

Option A. 57.14 Ω

Explanation:

From the question given above, the following data were obtained:

Resistor 1 (R₁) = 100 Ω

Resistor 2 (R₂) = 400 Ω

Resistor 3 (R₃) = 200 Ω

Equivalent Resistor (Rₚ) =?

The equivalent resistor in the above circuit can be obtained as follow:

1/Rₚ = 1/R₁ + 1/R₂ + 1/R₃

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1/Rₚ = (4 + 1 + 2)/400

1/Rₚ = 7/400

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Rₚ = 400/7

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