4 years ago

In your own words..Describe Friction Force.. In your own words..describe Applied force...

2 answers:

6 0

Friction is like when u take two stick's and rub it together to make fire when you use friction it can produce heat.

Applied force is like and applied to an object or person if a person is pushing a desk across the room then there is applied force

BARSIC [14]4 years ago

5 0

I think force is something to do with a force being applied to a movement or is just to pull but not sure sorry if this aint right

You might be interested in

During tug-of-war, team A does 2.20*10^5 J of work in pulling team B 8.00m. What average force did team A exert

Talja [164]

As we know that work done is defined as product of force and displacement

so here we will have

$W = F.d$

so here we know that

$W = 2.20 \times 10^5 J$

also we know that

$d = 8.00 m$

now we will have

$2.20 \times 10^5 = F(8.00)$

$F = \frac{2.20 \times 10^5}{8}$

$F = 27500 N$

so it will have 27500 N force on it

4 0

3 years ago

What is important when it comes to winning

Dmitry_Shevchenko [17]

Answer:

satisfaction, enjoyment and fair play

3 0

3 years ago

Read 2 more answers

HELP

BaLLatris [955]

The part of the electromagnetic spectrum has a shorter wavelength than ultraviolet light is x-rays.

3 0

3 years ago

Read 2 more answers

1. Mean Billy is standing on a bridge, waiting for his sister to walk underneath so that he can drop his vanilla ice cream cone

vovikov84 [41]

Answer:

fdghgjkk , mmn xgwvdkqgeb e keqwkclhehjq qbqlq.bq;q

Explanation:

8 0

3 years ago

An orange light (f = 5.2 * 10'4Hz) is

KonstantinChe [14]

Answer:

2.145×10^-10 V or 0.2145nV

Explanation:

From hf=eV

h= Plank's constant = 6.6×10^-34JS

f= frequency of the electromagnetic wave = 5.2×10^4 Hz

e= electronic charge= 1.6×10^-19 C

V= voltage

V= hf/e

V= 6.6×10^-34JS × 5.2×10^4 Hz/ 1.6×10^-19 C

V= 2.145×10^-10 V or 0.2145nV

Therefore the voltage created is 2.145×10^-10 V or 0.2145nV

7 0

3 years ago