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IgorLugansk [536]
3 years ago
8

What quantities determine the resistance of a piece of material? Choose all that apply.

Physics
1 answer:
bija089 [108]3 years ago
7 0

Answer:

Option (a), (b) and (c)

Explanation:

The resistance of a conductor depends on the length of the conductor, area of crossection of the conductor and the nature of the conductor.

The formula for the resistance is given by

R = ρ x l / A

Where, ρ is the resistivity of the conductor, l be the length of the conductor and A be the area of crossection of the conductor.

So, It depends on the length, area and the type of material.

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What is the density of an object that has a mass of 30 g and a volume of 20cm cubed/ to the third power?
Ksenya-84 [330]

Answer:

d= 1.5 g/cm3

Explanation:

datos

m= 30g

v= 20cm3

d=?

formula

d= m / v

solución

d= 30g / 20cm3 = 1.5g/cm3

6 0
2 years ago
What is the volume of a cone with a height of 27 cm
JulijaS [17]

Explanation:

→ Volume of cone = πr² × h/3

Here,

  • Radius (r) = 13 cm
  • Height (h) = 27 cm

→ Volume of cone = π(13)² × 27/3 cm³

→ Volume of cone = 169π × 9 cm³

→ Volume of cone = 1521π cm³

→ Volume of cone = 1521 × 22/7 cm³

→ Volume of cone = 33462/7 cm³

→ <u>Volume of cone = 4780.28 cm³</u>

4 0
3 years ago
Explain why offspring may or may not resemble either parent
katen-ka-za [31]
The offspring can have some features for the parents relatives and can look nothing like the parents. They can look exactly alike to more of one parent then the other or have features from both parents as well
Hope this helps :3
6 0
3 years ago
Read 2 more answers
A 6.3 g bullet leaves the muzzle of a rifle with a speed of 596.2 m/s. what constant force is exerted on the bullet while it is
ivanzaharov [21]
<span>anwser will be 

F = ma

where 

F = force exerted on the bullet 
m = mass of the bullet = 5 gm (given) = 0.005 kg. 
a = acceleration of the bullet 

Substituting appropriately, 

F = 0.005a --- call this Equation 1 

Next working equation is 

Vf^2 - Vo^2 = 2as 

where 

Vf = velocity of the bullet as it leaves the muzzle = 326 m/sec (given) 
Vo = initial velocity of bullet = 0 
a = acceleration of bullet 
s = length of the rifle's barrel 

Substituting appropriately, 

326^2 - 0 = 2(a)(0.83) 

a = 64,022 m/sec^2 

the anwser will be
Substituting this into Equation 1, 

F = 0.005(64,022) 

F =320.11 Newtons 

Hope this helps. </span><span>
</span>
8 0
3 years ago
A 73-kg boy is surfing and catches a wave which gives him an initial speed of 1.6 m/s. He then drops through a height of 1.60 m,
Gnesinka [82]

To solve this problem it is necessary to apply the concepts related to the Conservation of Energy, for which it is necessary that any decrease made through the potential energy, is equivalent to the gain given in the kinetic energy or vice versa.

Mathematically this can be expressed as

KE_i+PE_i = KE_f+PE_f

Since there is no final potential energy (the height is zero), and the initial potential energy is equivalent to the work done we have to

W = KE_f-KE_i-PE_i

W = \frac{1}{2}mv_f^2-\frac{1}{2}mv_i^2 -mgh

W =\frac{1}{2} m(v_f^2-v_i^2)-mgh

W= \frac{1}{2}(73)(8.5^2-1.6^2)-(73*9.8*1.6)

W= 1399.045J

W= 1.4kJ

Therefore the non-conservative work was done on the boy is 1.4kJ

4 0
3 years ago
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