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IRINA_888 [86]
3 years ago
9

Which of the following trigonometric ratios has a value that is undefined?

Mathematics
1 answer:
masya89 [10]3 years ago
3 0

Answer:

it is sin C

Step-by-step explanation:


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Which equation does the graph of the systems of equations solve?
DiKsa [7]

Answer:

-1/3x+3 = x-1

Step-by-step explanation:

The solution is (3,-2)

Check and see if the point solves the equation

-1/3x+3 = x-1

-1/3(3) +3 = 3-1

-1+3 = 3-1

2=2 yes

8 0
2 years ago
Quadrilateral ABCD is reflected across the x-axis. What are the coordinates of quadrilateral A'B'C'D? please help it's for a qui
Montano1993 [528]

Answer:

i think its c

Step-by-step explanation:

4 0
2 years ago
Please help me with these questions
d1i1m1o1n [39]

Problem 5)

The bases are the same, so we add the exponents when multiplying something like this out. We have -5+7 = 2 as the final exponent meaning that 5^2 = 25

<h3>Answer: Choice B) 25</h3>

=============================================

Problem 6)

We can multiply the exponents (t^8)^2 = t^(8*2) = t^16

Or we can expand out (t^8)^2 to get (t^8)*(t^8), then add the exponents from here to get t^(8+8) = t^16. Either way we get the same answer

<h3>Answer: Choice C) t^16</h3>

=============================================

Problem 7)

The negative exponent indicates we will apply the reciprocal to get that exponent to a positive number. The rule is x^(-k) = 1/(x^k)

So 5^(-4) = 1/(5^4) = 1/625 and (t^3)^(-4) = t^(3*(-4)) = t^(-12) = 1/(t^12)

Put together, we end up with 1/(625t^12)

<h3>Answer: Choice C) 1 over 625t^12</h3>
5 0
3 years ago
I WILL GIVE BRAINLIEST TO WHOEVER IS CORRECT.
zlopas [31]
In a function, each x-coordinate can be used only once.
If you have two points, one above the other on the same vertical line, it is not a function.
You are correct.
4 0
3 years ago
Read 2 more answers
Suppose sin(A)=-0.78. use the trig identity sin^2(A)+cos^2(A)=1 and the trig identity tan(A) = sin(A)/cos(A) to find tan(A) in q
Paladinen [302]

In quadrant IV, \cos(A) is positive. So

\sin^2(A) + \cos^2(A) = 1 \implies \cos(A) = \sqrt{1-\sin^2(A)} \approx 0.6258

Then by the definition of tangent,

\tan(A) = \dfrac{\sin(A)}{\cos(A)} \approx \dfrac{-0.78}{0.6258} \approx \boxed{-1.2465}

5 0
2 years ago
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