Answer: 1a. $190
b. The total cost of making 20 bracelets.
c. $350
d. The total cost of making 100 bracelets.
e. $1150
f. The total cost of making 500 bracelets.
g. 150 bracelets
h. 425 bracelets
Step-by-step explanation:
1a. C(20)=150+2(20)
C(20)=150+40
C(20)=$190
b. The total cost of making 20 bracelets.
c. C(100)=150+2(100)
C(100)=150+200
C(100)=$350
d. The total cost of making 100 bracelets.
e. C(500)=150+2(500)
C(500)=150+1000
C(500)=$1150
f. The total cost of making 500 bracelets.
g. 450=150+2b
2b=300
b=150 bracelets
h. 1000=150+2b
2b=850
b=425 bracelets
Answer: 
Step-by-step explanation:
We need;
We don't have the radius, but we do have the diameter. A diameter is twice the radius. Therefore, we can divide the diameter by 2 in order to obtain the radius.
Now plug this info into the formula.
![(3.14)(12yd)[(12yd)+\sqrt{(18yd)^2+(12yd)^2} ]](https://tex.z-dn.net/?f=%283.14%29%2812yd%29%5B%2812yd%29%2B%5Csqrt%7B%2818yd%29%5E2%2B%2812yd%29%5E2%7D%20%5D)
Let's solve the square root first.
![(3.14)(12yd)[(12yd)+\sqrt{324yd^2+144yd^2} ]](https://tex.z-dn.net/?f=%283.14%29%2812yd%29%5B%2812yd%29%2B%5Csqrt%7B324yd%5E2%2B144yd%5E2%7D%20%5D)
![(3.14)(12yd)[(12yd)+\sqrt{468yd^2} ]](https://tex.z-dn.net/?f=%283.14%29%2812yd%29%5B%2812yd%29%2B%5Csqrt%7B468yd%5E2%7D%20%5D)
![(3.14)(12yd)[(12yd)+\sqrt{468yd^2} ]\\(3.14)(12yd)(12yd+21.63yd)](https://tex.z-dn.net/?f=%283.14%29%2812yd%29%5B%2812yd%29%2B%5Csqrt%7B468yd%5E2%7D%20%5D%5C%5C%283.14%29%2812yd%29%2812yd%2B21.63yd%29)
Now solve the sum
Multiply
(−8.5)(−5)( −2)
This is a multiplication problem, so we can just multiply from left to right:
-8.5 x -5 = 42.5
42.5 x -2 = -85 (negative 85)
Hello,
The first step is to see that sides OA, OC, OB are all equal because they are the radii of the circle. Knowing that those sides are equal means that we have isosceles triangles. That gives us that the base angles are the same.
In OAC, we can subtract 118 from 180 to give us 62 degrees for the 2 bases angles. This would make each angle 31 degrees.
In OBC, the base angles are already 31, leaving the other angle 118.
There we have all the angles the same and 2 sides the same.
You could use SAS or ASA to prove that the triangles are congruent.
I hope this helps!
Good luck,
MrEquation
