Step-by-step explanation:
v=u+at
v=2+(-5)<u>1</u>
<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>2
v=2-2.5
v=-0.5m/s²
hope it helps.
Answer:
im 12!! how do you do this
Step-by-step explanation:
Answer:

Step-by-step explanation:
we know that
The area of the figure is equal to the area of rectangle plus the area of two semicircles
<u>The area of rectangle is equal to</u>

<u>The area of the small semicircle is equal to</u>

-----> radius is half the diameter
substitute

<u>The area of the larger semicircle is equal to</u>

-----> radius is half the diameter
substitute

The area of the figure is equal to

Answer:
Therefore $98 is be charged a bus containing 30 people.
Step-by-step explanation:
Given that,
A state park charges an entrance fee based on the number of people in vehicle.
Let the entry fee for the vehicle be E and entry fee for each person be x.
Then
C= E+(P×x)
C= Total charge in $
E= entry fee for a vehicle
P=No. of person
x= Entry charge per person.
Given A car containing 2 people charged $14
C=$14, P=2
∴14= E+(2× x)
⇒E+2x=14.....(1)
Again A car containing 4 people charged $20
C=$20, P=4
∴20= E+(4× x)
⇒E+4x=20.....(2)
Subtract (1) from (2), we get
E+4x-(E+2x)= 20-14
⇒E+4x-E-2x=6
⇒2x=6
⇒x=3
Putting the value of x in equation (1)
E+(2×3)=14
⇒E=14-6
⇒E=8
Therefore E=$8 and x=$3
Next we check whether our assumption is correct or wrong. Putting the value of E and x for third case
Here P= 8
Therefore C= E+(P×x)
= 8+(8× 3)
=8+24
=$32
Therefore our assumption is correct.
Now C=? , P= 30
The charged for the 30 people is
C= $[8+(30×3)]
=$[8+90]
=$98
Therefore $98 is be charged a bus containing 30 people.
Recall the Maclaurin expansion for cos(x), valid for all real x :

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

The first 3 terms of the series are

and the general n-th term is as shown in the series.
In case you did mean cos(√(5x)), we would instead end up with

which amounts to replacing the x with √x in the expansion of cos(√5 x) :
