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3 years ago

Simplify each expression. Then state the coefficient of the variable in each expression. 1. U + u + u + u

Mathematics

1 answer:

Pani-rosa [81]3 years ago

3 0

Answer:

4u
the coefficient is 4

Step-by-step explanation:

Using the distributive property, we can write the expression as ...

(1 + 1 + 1 + 1)u = 4u

The coefficient of the variable is 4 in the simplified expression.

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A standard I.Q. test produces normally distributed results with a mean of 104 and a standard deviation of 16 for 52,000 students

LUCKY_DIMON [66]

Answer:

maybe 250

Step-by-step explanation:

7 0

3 years ago

I NEED HELP PLEASE ?!!

Fittoniya [83]

The circle equation is in the format (x – h)² + (y – k)² = r², with the center being at the point (h, k) and the radius being "r".

QUESTION 11.
Equation x²+y²+10x-14y-7 =0 can be rewritten as: x²+10x+25 + y² -14y + 49 -7 - 25 - 49=0
It can be factories as (x + 5)² + (y – 7)² = 9²

Therefore the radius equals 9 and the center is (-5,7)

QUESTION 12.
From equation (x + 4)² + y² = 121

The radius equals √121 = 11 and the center is (-4,0)

QUESTION 13.
As there are missing information in the question, I can't assist. However, you can use the general circle equation (x – h)² + (y – k)² = r² to solve the question.

Finally equations 14 & 15 aren't linear.

Hope that helps you :)

5 0

3 years ago

Y+3x=8;x=1,0,3 what is answer

Lana71 [14]

The X=1 is Y= 5
The x=0 is Y= 8
The x=3 is Y= -1

6 0

3 years ago

M∠6 is (2x – 5)° and m∠8 is (x + 5)°. What is m∠3?

erastovalidia [21]

I hope this helps you

4 0

3 years ago

Read 2 more answers

Helpppp pleaseeeeeeeeeeeeeee

Vesna [10]

Answer:

Find below the calculations of the two areas, each with two methods. The results are:

Upper triangle:

$Area=5000\sqrt{3}units^2$

Lower triangle:

$Area=14,530m^2$

Explanation:

A) Method 1

When you are not given the height, but you are given two sides and the included angle between the two sides, you can use this formula:

$Area=side_1\times side_2\times sin(\alpha)$

Where, $\alpha$ is the measure of the included angle.

1. Upper triangle:

$side_1=200units\\ \\ side_2=100units\\ \\ \alpha =60\º\\ \\ Area=200units\times 100units\times sin(60\º)/2\\ \\ Area=5000\sqrt{3}units^2$

2. Lower triangle:

$side_1=231m\\ \\ side_2=150m\\ \\ \alpha =123\º\\ \\ Area=231m\times 150m\times sin(123\º)/2\\ \\ Area=14,529.96m^2\approx14,530m^2$

B) Method 2

You can find the height of the triangle using trigonometric properties, and then use the very well known formula:

$Area=(1/2)\times base\times height$

Use it for both triangles.

3. Upper triangle:

The trigonometric ratio that you can use is:

$sine(\alpha)=opposite\text{ }leg/hypotenuse$

Notice the height is the opposite leg to the angle of 60º, and the side that measures 100 units is the hypotenuse of that right triangle. Then:

$sin(60\º)=height/100units\\ \\ height=sin(60\º)\times100units\\ \\ height=50\sqrt{3}units$

$Area=(1/2)\times base\times height=(1/2)\times 200units\times 50\sqrt{3}units=5,000\sqrt{3}units^2$

3. Lower triangle:

$sin(180\º-123\º)=height/231m\\ \\ height=sin(57\º)\times 231m\\ \\ height=193.7329m^2$

$Area=(1/2)\times base\times height=(1/2)\times 150m\times 193.7329m^2\\\\ Area=14,529.96m^2\approx 14,530m^2$

5 0

3 years ago