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Nesterboy [21]
3 years ago
6

A standard I.Q. test produces normally distributed results with a mean of 104 and a standard deviation of 16 for 52,000 students

in grade 12 in the state. Approximately how many of these students would have I.Q.s above 120?
Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
7 0

Answer:

maybe 250

Step-by-step explanation:

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How many times does 6 go into 64
Bumek [7]
6 goes into 64 ten times with a remainder of 4
you know that
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A rectangles tabletop has a length of 4 3/4 feet and a area of 11 7/8 square feet what is the width of the tabletop
Natalija [7]
Area is length times width. Therefore, width is area divided by length. Convert 11 7/8 to the improper fraction 95/8 and convert 4 3/4 to 19/4. Then, you can fine 95/8 divided by 19/4 by flipping the second fraction and multiplying so that you have 95/8 times 4/19. 4 times 95 is 380 and 8 times 19 is 152. Therefore, the answer is 380/152. This is equivalent to 5/2 or 2.5. 
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What could be the intersection of the plane PRS and plane QRS
MrRa [10]
The plane PRS passes through the points P, R and S. So it contains the line RS. Also the plane QRS passes through the points Q, R and S. So it contains the line RS as well. Since both the planes contain the line RS, the line RS must be the intersection of plane PRS and QRS
6 0
2 years ago
What percent is 18 of 20
algol13

Answer:

90%

Step-by-step explanation:

  1. \frac{18}{20} = \frac{90}{100}  
  2. \frac{90}{100} = 90%

I hope this helps!

7 0
3 years ago
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You were testing orange juice recipes it’s recipe calls for orange juice concentrate and water mix one has 4 cups of concentrate
Sav [38]

Answer:

First mixed is the most orangey.

Step-by-step explanation:

First:

Orange\ juice\ concentrate=4\ cups\\\\Water=6\ cups\\\\Tota\ content=4+6=10\ cups\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{Orange\ juice\ concentrate}{Total\ amount}\times 100\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{4}{10}\times 100=40\%

Second:

Orange\ juice\ concentrate=1\ cups\\\\Water=3\ cups\\\\Tota\ content=1+3=4\ cups\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{Orange\ juice\ concentrate}{Total\ amount}\times 100\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{1}{4}\times 100=25\%

Third:

Orange\ juice\ concentrate=2\ cups\\\\Water=4\ cups\\\\Tota\ content=2+4=6\ cups\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{Orange\ juice\ concentrate}{Total\ amount}\times 100\\\\Percentage\ of\ orange\ juice\ concentrate=\frac{2}{6}\times 100=33.33\%

First mixed has highest percentage of orange juice. Hence first mixed is the most orangey.

4 0
3 years ago
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