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Scorpion4ik [409]
4 years ago
6

PLEASEE HELPP ANYONE

Mathematics
2 answers:
Inga [223]4 years ago
5 0

Answer:

D is correct. x>2 the growth rate of the exponential function exceed the growth rate of the linear function.

Step-by-step explanation:

We are given a linear function and an exponential function in graph.

We need to find interval when growth rate of the exponential function exceed the growth rate of the linear function.

\text{Linear function: }L(x)=2x

\text{Exponential function: }E(x)=2^x

Option A) When x<1

Growth rate of linear function = 2

Growth rate of Exponential function = 0.75

When x<1 , growth rate of exponential function is less than linear function.

Option B) When 0≤x≤1  

Growth rate of linear function = 2

Growth rate of Exponential function = 1

When 0≤x≤1  , growth rate of exponential function is less than linear function.

Option C) When 1≤x≤2

Growth rate of linear function = 2

Growth rate of Exponential function = 2

When 1≤x≤2  , growth rate of exponential function is equal to linear function.

Option D) When x>2  

Growth rate of linear function = 2

Growth rate of Exponential function = 4

When x>2  , growth rate of exponential function is exceed the growth rate of  linear function.

Thus, x>2 the growth rate of the exponential function exceed the growth rate of the linear function.


sattari [20]4 years ago
3 0
Answer: D) x>2.

This is because the slope of the exponential function is clearly greater than the linear function from 2 on the x=axis forward. 
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P-9=15 simplify answer
stira [4]

Answer:

p=24

(Please vote me Brainliest if this helped!)

Step-by-step explanation:

p-9=15

\mathrm{Add\:}9\mathrm{\:to\:both\:sides}

p-9+9=15+9

\mathrm{Simplify}

p=24

4 0
4 years ago
1. Find the value of x <br> x°<br> 117°<br> 66°
ra1l [238]

Answer:

1. 1

1. 13π.

--

20

explain:

1. 1 because any any non-zero expression raised to the power of 0 equals 1

13π.

2. --. because to convert into radian measure multiply by. π

20. ----

180°

6 0
3 years ago
A recent study focused on the number of times men and women send a WeChat message in a day. The information is summarized next.
Ratling [72]

Answer:

1)Null hypothesis:\mu_{men}=\mu_{women}

Alternative hypothesis:\mu_{men} \neq \mu_{women}

2) Two critical values are z_{\alpha/2}=-2.58 and z_{1-\alpha/2}=2.58

3) z=-2.40  

4) p_v =2*P(z

5) Comparing the p value with the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis, and a would NOT be a significant difference in the mean number of times men and women send a Twitter message in a day.

Step-by-step explanation:

Data given and notation

\bar X_{men}=23 represent the mean for the sample men

\bar X_{women}=28 represent the mean for the sample women

\sigma_{men}=5 represent the population standard deviation for the sample men

\sigma_{women}=10 represent the population standard deviation for the sample women

n_{men}=25 sample size for the group men

n_{women}=30 sample size for the group women

t would represent the statistic (variable of interest)

\alpha=0.01 significance level provided

1)Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the means for the two groups are different, the system of hypothesis would be:

Null hypothesis:\mu_{men}=\mu_{women}

Alternative hypothesis:\mu_{men} \neq \mu_{women}

Since we know the population deviations for each group, for this case is better apply a z test to compare means, and the statistic is given by:

z=\frac{\bar X_{men}-\bar X_{women}}{\sqrt{\frac{\sigma^2_{men}}{n_{men}}+\frac{\sigma^2_{women}}{n_{women}}}} (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

2)Determine the critical value(s).

Based on the significance level\alpha=0.01 and \alpha/2=0.005 we can find the critical values with the normal standard distribution, we are looking for values that accumulates 0.005 of the area on each tail on the normal distribution.

For this case the two values are z_{\alpha/2}=-2.58 and z_{1-\alpha/2}=2.58

3) Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

z=\frac{23-28}{\sqrt{\frac{5^2}{25}+\frac{10^2}{30}}}}=-2.40  

4)What is the p-value for this hypothesis test?

Since is a bilateral test the p value would be:

p_v =2*P(z

5)Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we FAIL to reject the null hypothesis, and a would NOT be a significant difference in the mean number of times men and women send a Twitter message in a day.

4 0
3 years ago
Write 18/27 in simplest form.
Deffense [45]
The simplest form of 18/27 is 2/3
:)
4 0
3 years ago
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The formula PV=300R is used in chemistry. How can this formula be solved for P?
denis-greek [22]
Just divide V to both sides giving you P= 300P/V
4 0
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