Answer:
30 meters^3
Step-by-step explanation:
volume is l x w x h
so the formula would be 5x3x2
which is 15x2
therefore the answer is 30
Please provide more information for a anwser
Complete Question
A survey is planned to estimate the proportion of voters who support a proposed gun control law. The estimate should be within a margin of error of ±5% with 90% confidence, and we do not have any prior knowledge about the proportion who might support the law. How many people need to be included in the sample?
Round your answer up to the nearest integer.
sample size = _____
Answer:
The sample size is
Step-by-step explanation:
From the question we are told that
The margin of error is E = 5% = 0.05
Generally given that there was no prior knowledge about the proportion of who might support the law, we will assume the sample proportion to be
![\^ p = 0.5](https://tex.z-dn.net/?f=%5C%5E%20p%20%3D%20%200.5)
From the question we are told the confidence level is 90% , hence the level of significance is
=>
Generally from the normal distribution table the critical value of
is
Generally the sample size is mathematically represented as
=>
=>
Answer:
![p_v= P(\chi^2_{9}>11.517)=0.2419](https://tex.z-dn.net/?f=p_v%3D%20P%28%5Cchi%5E2_%7B9%7D%3E11.517%29%3D0.2419)
And on this case if we see the significance level given
we see that
so we fail to reject the null hypothesis that the observed outcomes agree with the expected frequencies at 10% of significance.
Step-by-step explanation:
A chi-square goodness of fit test determines if a sample data obtained fit to a specified population.
represent the p value for the test
O= obserbed values
E= expected values
The system of hypothesis for this case are:
Null hypothesis: ![O_i = E_i[/tex[Alternative hypothesis: [tex]O_i \neq E_i](https://tex.z-dn.net/?f=O_i%20%3D%20E_i%5B%2Ftex%5B%3C%2Fp%3E%3Cp%3EAlternative%20hypothesis%3A%20%5Btex%5DO_i%20%5Cneq%20E_i%20)
The statistic to check the hypothesis is given by:
![\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}](https://tex.z-dn.net/?f=%5Cchi%5E2%20%3D%5Csum_%7Bi%3D1%7D%5En%20%5Cfrac%7B%28O_i%20-E_i%29%5E2%7D%7BE_i%7D)
On this case after calculate the statistic they got: ![\chi^2 = 11.517](https://tex.z-dn.net/?f=%5Cchi%5E2%20%3D%2011.517)
And in order to calculate the p value we need to find first the degrees of freedom given by:
, where k represent the number of levels (on this cas we have 10 categories)
And in order to calculate the p value we need to calculate the following probability:
![p_v= P(\chi^2_{9}>11.517)=0.2419](https://tex.z-dn.net/?f=p_v%3D%20P%28%5Cchi%5E2_%7B9%7D%3E11.517%29%3D0.2419)
And on this case if we see the significance level given
we see that
so we fail to reject the null hypothesis that the observed outcomes agree with the expected frequencies at 10% of significance.