Solution:
x y ║ z w→→Given
Also, x z is a transversal, that intercepts x y and z w.
So, ∠ x z w=∠z x y→→Alternate interior angles as, x y ║ z w.
Also, v is point of intersection of x z and y w.
∠ x v y ≅ ∠ z v w→→[ Vertically opposite angles]
So,→→ Δ x y v ~ Δ z w v⇒⇒[Angle-Angle Similarity]
Answer:
There is enough evidence to support the claim that the population mean is greater than 100
Step-by-step explanation:
<u>Step 1</u>: We state the hypothesis and identify the claim
and
(claim)
<u>Step 2</u>: Calculate the test value.


<u>Step 3</u>: Find the P-value. The p-value obtained from a calculator is using d.f=39 and test-value 1.126 is 0.134
<u>Step 4</u>: We fail to reject the null hypothesis since P-value is greater that the alpha level. (0.134>0.05).
<u>Step 5</u>: There is enough evidence to support the claim that the population mean is greater than 100.
<u>Alternatively</u>: We could also calculate the critical value to obtain +1.685 for
and d.f=39 and compare to the test-value:
The critical value (1.685>1.126) falls in the non-rejection region. See attachment.
NB: The t- distribution must be used because the population standard deviation is not known.
Answer: The mean of this distribution = 61.95
The standard deviation of this sampling distribution (i.e., the standard error= 0.048
Step-by-step explanation:
Given : Data from the U.S. Department of Education indicates that 59% of business graduate students from private universities had student loans.
i.e. proportion of business graduate students from private universities had student loans : p=0.59
sample size : n=105
Then , the mean of the distribution is given by :-

∴The mean of this distribution = 61.95
Then standard deviation of this sampling distribution is given by :-

∴The standard deviation of this sampling distribution (i.e., the standard error= 0.048