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BigorU [14]
2 years ago
11

If a number cube is rolled, what is the probability of rolling on a prime number

Mathematics
1 answer:
snow_lady [41]2 years ago
3 0

Answer:

1/2 chance

Step-by-step explanation:

A cube has 6 sides. 1, 2, 3, 4, 5, 6.

2, 3, and 5 are primes.

3/6=1/2.

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I need help with this one
Aleks [24]

Answer:

c

Step-by-step explanation:

4 0
2 years ago
X-1=y what is the answer plz give me the answer
guajiro [1.7K]

Answer:

<h2>X = 0</h2><h2>Y = 1</h2>

First of all, observe that this is a line, since you can rewrite the equation as y−x+1=0 , which follows the pattern of the generic line ax+by+c=0 .

To draw a line you need two of its points, which you can connect.

To find two points, you can plug any value for one variable, and solve for the other.

For example, let's choose

x=0 . The equation becomes

0−1=y , and so y=−1 .

The first point is thus (0,−1).

Then, let's choose

x=1 . The equation becomes 1−1=y , and so y=0 . The first point is thus

(1,0).

Now you only need to draw the points

(0,−1)

Step-by-step explanation:

Hope it is helpful...

6 0
3 years ago
What is 1/100 of 200
chubhunter [2.5K]
2/200 i'm just typing this to fill in the how many letters I have to type
8 0
3 years ago
Read 2 more answers
Jason and Beth are married and don’t have any kids yet. They are out of debt except for their house, and they have a full emerge
UNO [17]

Answer:

Pay cash for the whole car.

Step-by-step explanation:

4 0
3 years ago
One day, Karen bought 22 random cans of soup from a grocery store. Suppose that 5% of cans sold at that particular grocery store
zimovet [89]

Answer:

0.6765 = 67.65%

Step-by-step explanation:

This situation can be treated as a binomial model with probability of success (dented can) of p = 0.05.

In 22 random trials, the probability of at least one success is determined by:

P(X>1) = 1-P(X=0)\\P(X>1) = 1 - (1-p)^{22}\\P(X>1) = 1 - (1-0.05)^{22}\\P(X>1) =0.6765

The probability that Karen has bought at least one dented can is 0.6765 or 67.65%.

7 0
3 years ago
Read 2 more answers
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