Answer:
(-b/2a, b^2/(4*a) - b^2/2a + c)
Step-by-step explanation:
For a general parabola:
y = a*x^2 + b*x + c
We can write the vertex as:
(h, k)
The x-value of the vertex is the value of the axis of symmetry.
Then we have:
h = x = -b/2a
Now we need to find the y-value of the vertex.
To do that, we just replace the variable "x" by the x-value of the vertex in our equation, so we get:
k = y = a*(-b/2a)^2 + b*(-b/2a) + c
k = b^2/(4*a) - b^2/2a + c
Then the coordinates of the vertex are:
(h, k) = (-b/2a, b^2/(4*a) - b^2/2a + c)
Answer:
9
Step-by-step explanation:
In the notation of a function f(x) = x+8, for input x=1 the output would be 9. And (1,9) would be an (x,y) pair that fits the function.
The answer is A
Med range = 65+15 /2 = 40
Range = 65-15=50
<span>A quarter of the marbles are red, so there are 124/4 = 31 red marbles. The rest are blue, so there are 124 - 31 = 93 blue marbles.</span>
By direct correspondence AB = PQ
