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Varvara68 [4.7K]
3 years ago
12

Solve the logarithmic equation. Be sure to reject any value of log (X + 8) = log x + log 8​

Mathematics
2 answers:
iogann1982 [59]3 years ago
8 0

Answer:

x =  \frac{8}{7}

Step-by-step explanation:

log(x + 8)  =  log(x)  +  log(8)  \\ (x + 8) = 8x \\ x + 8 = 8x \\ 8 = 8x - x \\ 8 = 7x \\  \frac{8}{7} =  \frac{7x}{7}  \\ x =  \frac{8}{7}

swat323 years ago
6 0

Answer:

x = 8/7

Step-by-step explanation:

log (X + 8) = log x + log 8​

We know that log a + log b = log ab

log (X + 8) = log 8x

Raise each side to base 10

10^log (X + 8) = 10^log 8x

x+8 = 8x

Subtract x from each side​

x+8-x = 8x-x

8 = 7x

Divide by 7

8/7 = 7x/7

8/7 =x

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4 0
3 years ago
James Has twO girls and his friend jEnnie has to girls how many girls do they have together
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Answer:

4

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total no. of girls James have = 2

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5 0
3 years ago
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In the month of June, the temperature in Johannesburg, South Africa, varies over the day in a periodic way that can be modeled a
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Answer:

T = - 7.5 Cos π/12( t - 4 ) + 10.5

Step-by-step explanation:

Given that the

Maximum temp. = 18 degree Celsius

Minimum temp. = 3 degree Celsius

The half way between 10 am and 10 pm is 4 am

The sine and cosine functions can be used to model fluctuations  in temperature data through out the year. An equation that can be used to model these data is of the form:

T = A cos B(t - C) + D, where A,B,C,D, are constants, T is the  temperature in °C and t is the hour (1–24)

A = amplitude = (Tmax - Tmin)/2

A = (3 - 18)/2 = - 15/2 = -7.5 ( note : after midnight)

B = 2π/24 = π/12

C = units translated to the right

C = 4

D = ymin + amplitude = units translated up

D = 7.5 + 3 = 10.5

The formula of the trigonometric function that models the temperature T in Johannesburg t hours after midnight we be

T = - 7.5 Cos π/12( t - 4 ) + 10.5

3 0
4 years ago
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Answer:

sine A = four-fifths

Step-by-step explanation:

You have a rectangle triangle ABC with hypotenuse AB 35, side CB 28 and side CA 21. The angle C is 90°.

In order to calculate sin A, you take into account that:

sinA=\frac{opposite\ side\ to\ A}{hypotenuse}

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You replace the numeric values of the hypotenuse and side BC in the formula for sinA:

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In order to simply the fraction, you divide both numerator and denominator by 7:

sinA=\frac{28/7}{35/7}=\frac{4}{5}

hence, the answer is

sine A = four-fifths

3 0
4 years ago
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