y = 9ln(x)
<span>y' = 9x^-1 =9/x</span>
y'' = -9x^-2 =-9/x^2
curvature k = |y''| / (1 + (y')^2)^(3/2)
<span>= |-9/x^2| / (1 + (9/x)^2)^(3/2)
= (9/x^2) / (1 + 81/x^2)^(3/2)
= (9/x^2) / [(1/x^3) (x^2 + 81)^(3/2)]
= 9x(x^2 + 81)^(-3/2).
To maximize the curvature, </span>
we find where k' = 0. <span>
k' = 9 * (x^2 + 81)^(-3/2) + 9x * -3x(x^2 + 81)^(-5/2)
...= 9(x^2 + 81)^(-5/2) [(x^2 + 81) - 3x^2]
...= 9(81 - 2x^2)/(x^2 + 81)^(5/2)
Setting k' = 0 yields x = ±9/√2.
Since k' < 0 for x < -9/√2 and k' > 0 for x >
-9/√2 (and less than 9/√2),
we have a minimum at x = -9/√2.
Since k' > 0 for x < 9/√2 (and greater than 9/√2) and
k' < 0 for x > 9/√2,
we have a maximum at x = 9/√2. </span>
x=9/√2=6.36
<span>y=9 ln(x)=9ln(6.36)=16.66</span>
the
answer is
(x,y)=(6.36,16.66)
Answer:
Estimate: 7
Actual: 6.63 (>)
Step-by-step explanation:
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Answer:
True
Step-by-step explanation:
Answer:
x=3
y=5
Step-by-step explanation:
x+5y=28 (i)
-x-2y=-13. (ii)
add equation 2 from equation 1
x+5y=28
-x-2y=-13
3y=15
y=5
put the value of y in equation 1
x+5y=28
x+5*5=28
x+25=28
x=28-25
x=3
Answer:
x = 27
Step-by-step explanation:
To isolate x, we can multiply it by the reciprocal of the fraction (-3/2). We do the same to the -18.
Through cross-multiplication, -18/1 x -3/2 simplifies into -9/1 x -3/1 (because 2 goes into 2 once and 2 goes into -18 -9 times).
-9 x -3 = 27; therefore, x = 27
