Let quarters = q and
Dimes = d
We have 741 coins total so q + d = 741
Since quarters are 25 cents and Dimes are 10 cents then
25q + 10d = 10725 cents
Now we have 2 equations that we can solve using addition or substitution.
Using addition, first multiply the first equation by -10
-10 (q+d) = 741 (-10)
-10q - 10d = -7410
Now add the equations together
(-10q -10d = -7410)
+ (25q + 10d =10725)
________________
15q = 3315
q = 3315 / 15
q = 221
this is the number of quarters
Now plug this back into the original equation
q + d = 741
221 + d = 741
d = 741 - 221
d = 520
There are 520 dimes
0.000565 - this is a simple standard form question (if the 10 is to the power of a negative number, the answer will always be extremely low!)
Answer:
The correct answer is x = 6.
Step-by-step explanation:
To solve this problem, we first must recognize that DE + EF = DF.
From this information, we can set up the following equation when we substitute in the given values:
DE + EF = DF
(4x-1) + 9 = 9x - 22
Our first step is going to be to combine like terms on the left side of the equation. This is modeled below:
4x - 1 + 9 = 9x - 22
4x + 8 = 9x - 22
Then, we should subtract 4x from both sides of the equation.
8 = 5x - 22
Now, we can add 22 to both sides of the equation.
30 = 5x
Finally, we can divide both sides by 5.
x = 6
Therefore, the correct answer is x = 6.
Hope this helps!
Answer:
Answer is <em>n</em><em>/</em><em>2</em>
Step-by-step explanation:
I started with the constant n
In second step I divided the n by 2
<em>HAVE A NICE DAY</em><em>!</em>
<em>THANKS</em><em> </em><em>FOR GIVING ME THE OPPORTUNITY TO</em><em> </em><em>ANSWER YOUR QUESTION</em><em>. </em>
Since one side is 40°, you subtract that from 180.
180° - 40°= 140°.
So therefore your missing side lengths are 140, 40, and 140.
hopefully this helps
