10% = 10g/100ml. Ergo, 15ml/100ml (10g) = 1500mg of KCL
.9% NACL = 9g/1000mL, Ergo = 9000mg NaCl
Now we have to figure out how many mEqs of each salt we have.
MW of NaCl = 58.5
MW of KCl = 74.5
So, in moles, we have:
1500 KCl / 74.5 = 20.13 mmol KCl
9000 NaCl / 58.5 = 153.85mmol NaCl
Because the valence of both ions is one, as an example, it would be both 20.13 mEq of Cl- and K+ from 20.13 mmoles of KCL.
So, just add the two together, 20.13 + 153.85 = 174-ish.
Answer: 400
Step-by-step explanation: So it’s Length, width, and height. so:
1: 10 times 8= 80
2= 80 times 5= 400u2
Be sure to box your answer.
Answer:
brainliest plss!!
Step-by-step explanation:
jkhujmmmmmjhhhhh
Answer:
xy = 1
k = 79
Step-by-step explanation:
Question One
The first and third frames look to me to be the same. I'll treat them that way.
y = x^2 Equate y = x^2 to the result of 2y + 6 = 2x + 6
2y + 6 = 2(x + 3) Remove the brackets
2y + 6 = 2x + 6 Subtract 6 from both sides
2y = 2x Divide by 2
y = x
Now solve these two equations.
so x^2 = x
x > 0
1 solution is x = 0 from which y = 0. This won't work. x must be greater than 0. So the other is
x(x) = x Divide both sides by x
x = 1
y = x^2 Put x = 1 into x^2
y = 1^2 Solve
y = 1
The second solution is
(1,1)
xy = 1*1
xy = 1
Answer: A
Question Two
square root(k + 2) - x = 0
Subtract x from both sides
sqrt(k + 2) = x Square both sides
k + 2 = x^2 Let x = 9
k + 2 = 9^2 Square 9
k + 2 = 81
k = 81 - 2
k = 79
Answer:
$225 of birthday money
Step-by-step explanation:
he spent 20 percent (1/5) of the money on dog treats, and the remaining 80 percent (4/5) went to 3 different charities. If $60 dollars were given to each charity, that means a total of $180 dollars was given to charity. if 4/5 of the money is equal to $180, we can divide 180 by 4 to get $45 dollars. this means that 1/5 of the birthday money would be equal to $45 dollars. so to find 5/5, or 100% of the money, simply multiply $45 by the denominator, 5, to get the answer. the total birthday money received was $225 dollars, and $45 dollars of that was used for dog treats.
