You have to deal with this type of question step by step. Firstly, you can figure out all the unknown values (such as sqrt x-3), by substituting x for 19, as you are trying to figure out f(x) when x=19. Therefore:
x+2=21
sqrt(x-3)=sqrt(19-3)=sqrt 16=4
Now the equation is easier to handle:
3/21 - 4
We can write this as 3/21 - 4/1 , which equals -27/7.
For light: Inverse Square Law
<span>
The signal is weaken by the inverse square of the
difference of distances this means that one over the square of the
difference. </span>
<span>
</span>
Therefore, 70000LY / 141 LY =496.45 and that
squared =246462.602 times less signal, or 1/246462.602.
2 For a circular telescope like the
Arecibo radio telescope that equals Pi times the radius squared. Sensitivity
of the telescope depends on its area.<span>
The new telescope needs 246462.60 times that area to have
enough sensitivity </span>
<span>
<span>(150 x 150 x Pi) = 70 685 sq m area for the Arecibo telescope
and that times 246462.60
= 1.74212 x 10^10</span></span>
<span><span>
</span></span>
What is the diameter of a circle with that area?
<span>
<span>1. Divide the area by Pi = 5.548156 x 10^9
2. Take the square root of the result to find the radius = 74485.94293</span></span>
3. Multiply by 2 to find the diameter =
<span>148971.886</span>
Answer:
unlikey
Step-by-step explanation:
You write it as a ratio eg. SF(large→small)=20:7
Answer:
x = 11º
Step-by-step explanation:
1. Notice Parallel Lines
2. Understand Angle Relationships When Parallel Lines Are Present (e.g., alternate interior/exterior)
3. ∠CAB ≅ ∠DCA ∴ m∠CAB = 33º
4. Use exterior angle theorem: the sum of non-adjacent angles of the same triangle which the exterior angle is drawn is equal to the measure of that angle.
5. Therefore write and solve the equation 2x + 33º (sum of non-adjacent interior angles) = 5x (exterior angle).
- 2x + 33 = 5x (C.L.T or <u>C</u>ombine <u>L</u>ike <u>T</u>erms)
- 3x = 33 (inverse operations; divide by 3)
- x = 11º (remember to apply units)