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Rom4ik [11]
3 years ago
13

Given each of the following areas, what would be the radius of each circle? a. A = 530.66 m2 b. A = 907.46 sq. ft. c. A = 379.94

sq. mi. d. A = 1962.5 cm2
Mathematics
1 answer:
ra1l [238]3 years ago
3 0
Area for a circle is A= \pi r^2.  We will fill in each area and then solve for the radius.  530.66m^2= \pi r^2 and \frac{530.66m^2}{3.14}=r^2.  ∴169=r^2 and r = 13.  For b, 907.46ft^2= \pi r^2 and \frac{907.46ft^2}{3.14}=r^2.  289=r^2, ∴ r = 17.  For c, 379.94mi^2= \pi r^2, and \frac{379.94mi^2}{3.14}=r^2.  ∴, 121=r^2 and r = 11.  For d, 1962.5cm^2= \pi r^2, and \frac{1962.5cm^2}{3.14}=r^2.  ∴, 625=r^2 so r = 25.  And there you have it!
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The coordinates of the midpoint of CD with endpoint at C(-7,-2) and D(-3,-5) is E(-5, -3.5)

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Let (x, y) represent the coordinate of the midpoint E. Point E is the midpoint of CD, hence:

x = [(-7) + (-3)] / 2 = -5

y = [(-2) + (-5)] / 2 = -3.5

The coordinates of the midpoint of CD with endpoint at C(-7,-2) and D(-3,-5) is E(-5, -3.5)

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