Answer:
y=0x-1
Step-by-step explanation:
mx is our slope, while our b is always going to be our y intercepts
Add 7 both sides
5b>20
divide both sides by 5
b>4
Ok to start you need to break this into a net in your head. Next, calculate each triangle
(6*7)/2 = 21
Then, multiply each triangle by the amount of them.
21*4 = 84
Next, get the area of the square.
7*7 = 49
Lastly, add the triangles and the square up.
49 + 84 = 133
![\bf \qquad \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\\ r=rate\to r\%\to \frac{r}{100}\\ n= \begin{array}{llll} \textit{times it compounds per year} \end{array}\\ t=year \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Ctextit%7BCompound%20Interest%20Earned%20Amount%7D%0A%5C%5C%5C%5C%0AA%3DP%5Cleft%281%2B%5Cfrac%7Br%7D%7Bn%7D%5Cright%29%5E%7Bnt%7D%0A%5Cquad%20%0A%5Cbegin%7Bcases%7D%0AA%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%0AP%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5C%5C%0Ar%3Drate%5Cto%20r%5C%25%5Cto%20%5Cfrac%7Br%7D%7B100%7D%5C%5C%0An%3D%0A%5Cbegin%7Barray%7D%7Bllll%7D%0A%5Ctextit%7Btimes%20it%20compounds%20per%20year%7D%0A%5Cend%7Barray%7D%5C%5C%0At%3Dyear%0A%5Cend%7Bcases%7D)
![\bf 1.185\implies 1+0.185\qquad\quad and\quad n=1 \\\\\\ A=P\left(1+\frac{r}{n}\right)^{nt}\implies A=P\left(1+0.185\right)^{nt}\implies A=P\left(1+\frac{0.185}{1}\right)^{1\cdot t}](https://tex.z-dn.net/?f=%5Cbf%201.185%5Cimplies%201%2B0.185%5Cqquad%5Cquad%20and%5Cquad%20n%3D1%0A%5C%5C%5C%5C%5C%5C%0AA%3DP%5Cleft%281%2B%5Cfrac%7Br%7D%7Bn%7D%5Cright%29%5E%7Bnt%7D%5Cimplies%20A%3DP%5Cleft%281%2B0.185%5Cright%29%5E%7Bnt%7D%5Cimplies%20A%3DP%5Cleft%281%2B%5Cfrac%7B0.185%7D%7B1%7D%5Cright%29%5E%7B1%5Ccdot%20%20t%7D)
so, the percentage of the rate is 0.185, what's that as a percentage? well, 0.185 * 100, 18.5%.
Answer:
yes the answer is B
Step-by-step explanation:
Divide both sides by the numeric factor on the left side, then solve.