All categories

3 years ago

How do I solve 372 = -3x - 6(8x + 6)? I already know that x = -8, but I need to know the process of how to get it.

Mathematics

1 answer:

ziro4ka [17]3 years ago

3 0

The value of x is -8

Step-by-step explanation:

The steps of solving an equation of one variable

Simplify the two sides of the equation
Separate the variable in one side and the numerical term in the other side
Divide the both sides by the coefficient of the variable

∵ 372 = -3x - 6(8x + 6)

- Simplify the R.H.S. of the equation by multiplying the bracket by 6

∵ 372 = -3x - [6(8x) + 6(6)]

- You must put the square bracket because the sign in-front of 6

is (-) and the (-) changes the signs after it

∴ 372 = -3x - [48x + 36]

- Remember (-)(+) = (-), multiply the square bracket by (-)

∴ 372 = -3x - 48x - 36

- Add the like terms in the R.H.S.

∴ 372 = -51x - 36

- Add 36 to both sides to separate x in the R.H.S.

∴ 408 = -51x

- Divide both sides by -51 (coefficient of x)

∴ -8 = x

I hope these steps help you

The value of x is -8

Learn more:

You can learn more about the equations in brainly.com/question/11306893

#LearnwithBrainly

You might be interested in

The diagram below shows an Isosceles triangle. Label the base angles and the vertex

Dmitry [639]

The base angles of an isosceles triangle are equal

The base angles are 15 degrees, while the vertex angle is 150 degrees

The base angles are given as:

Base = (6a- 3) and (a + 12)

So, we have:

$\mathbf{6a -3 =a + 12}$

Collect like terms

$\mathbf{6a -a =3 + 12}$

$\mathbf{5a = 15}$

Divide both sides by 5

$\mathbf{a = 3}$

Substitute 3 for a in Base = (6a- 3),

$\mathbf{Base = 6 \times 3 - 3}$

$\mathbf{Base = 18 - 3}\\$

$\mathbf{Base = 15}$

So, the base angle is 15 degrees.

The vertex angle is calculated using:

$\mathbf{Vertex=180 -2 \times Base}$

So, we have:

$\mathbf{Vertex=180 -2 \times 15}$

$\mathbf{Vertex=150 }$

Hence, the vertex angle is 150 degrees

Read more about isosceles triangles at:

brainly.com/question/25739654

6 0

1 year ago

2/3(3/5x+9)=1/2(2x+40)<br><br> I posted this before but w/o the 1/2 on accident

andriy [413]

The answer and working are shown in the photo below

5 0

2 years ago

I have one qt of solution diluted out 1:4 How much do I need to add to end up with a final product that’s a 1:10 solution?

LenaWriter [7]

Answer:

1.1352 L

Step-by-step explanation:

L = qt 1.0567

qt = 0.946 L

1:4 = 5

0.946/5 = 0.1892 L one part

0.1892 x 11 = 2.0812 11 parts as 1+10 =11

Answer therefore is subtracting 5 from 11 parts to get the final 6 parts added = 2.0812 - 0.946

= 1.1352 L

7 0

2 years ago

Parallelogram PQRS is shown on the coordinate grid. Parallelogram PQRS is dilated with the origin as the center of dilation usin

Gwar [14]

Answer:

B) Parallelogram P'Q'R'S' is smaller than parallelogram PQRS, because the scale factor is less than 1.

Step-by-step explanation:

Given that Parallelogram PQRS is shown on the coordinate grid. Parallelogram PQRS is dilated with the origin as the center of dilation using the rule (x, y) → (0.75x, 0.75y) to create parallelogram P'Q'R'S'.

This means that sides of PQRS would be 0.75 times the sides of the original PQRS

Or PQRS will be larger

B) Parallelogram P'Q'R'S' is smaller than parallelogram PQRS, because the scale factor is less than 1.

is the right answer

7 0

2 years ago

Delta Airlines quotes a flight time of 2 hours, 5 minutes for its flights from Cincinnati toTampa. Suppose we believe that actua

siniylev [52]

Answer:

a) The graph of the probability density function for flight time is shown below.

b) 1/2

c) 0

d) 130 minutes

Step-by-step explanation:

Let's deal with the flight times in minutes instead of hours, and let T be the random variable that represents the flight time. T is uniformly distributed between 120 minutes and 140 minutes. The probability density function for T is given by

$f(t)=\frac{1}{140-120}=\frac{1}{20}$ for t in [120, 140]

a) The graph of the probability density function for flight time is shown below.

Delta Airlines quotes a flight time of 125 minutes for its flights from Cincinnati to Tampa.

b) The probability that the flight will be no more than 5 minutes late is given by

$P(T \leq 125 + 5) = P(T \leq 130) = \int\limits_{120}^{130}\frac{1}{20}dt = \frac{1}{20}(130-120)= \frac{1}{20}(10) = \frac{1}{2}$

c) The probability that the flight will be more than 10 minutes late is given by

$P(T \geq 125 + 10) = P(T \geq 135) = 0$ because the probability density function is zero for t outside of [120, 140]

d) The expected flight time is given by $E(T) = \frac{120+140}{2} = \frac{260}{2} = 130$ minutes

8 0

3 years ago