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Katarina [22]
3 years ago
9

The scale of the drawing was 1 centimeters:4 meters.What is the ratio of the drawing?

Mathematics
2 answers:
Tom [10]3 years ago
7 0

Answer:

1:400 w7uwuwwuwiwiwyyyuuiyy

muminat3 years ago
3 0

9514 1404 393

Answer:

  1 : 400

Step-by-step explanation:

A meter is 100 cm, so 4 m = 400 cm.

  1 cm : 4 m = 1 cm : 400 cm = 1 : 400

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A health club charges $35 a month for membership fees. Determine whether the cost of membership is proportional to the number of
SIZIF [17.4K]
Yes, the cost of membership is proportional to the number of months because for every 1 month it's $35 for membership fees
7 0
3 years ago
Find the absolute value of 2 and 2 3rd and negative 9 over 4
gayaneshka [121]

we are given

absolute value of 2 and 2 3rd and negative 9 over 4

Firstly , we need write it in terms of expression

2 and 2 3rd is

2+\frac{2}{3}

so, we get as

|2+\frac{2}{3} -\frac{9}{4} |

now, we can simplify it

Firstly , we will find common denominator

|\frac{2*12}{1*12} +\frac{2*4}{3*4} -\frac{9*3}{4*3} |

|\frac{24}{12} +\frac{8}{12} -\frac{27}{12} |

we can see that

all denominators are same

so, we can combine numerators

=|\frac{24+8-27}{12}  |

=|\frac{5}{12}  |

=\frac{5}{12}..............Answer

6 0
3 years ago
How do I write 3 2/3 in a from of a decimal?
Alisiya [41]
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4 0
3 years ago
A bag of candy weighs 25.62 ounces. A group of 4 friends is going to share the bag of candy equally.
saul85 [17]
Part A: 6.2
Part B:6.405
PArt C: The estimate was close to the real answer
4 0
3 years ago
If p=(-3,-2) and q=(1,6) are the endpoints of the diameter of a circle find the equation of the circle
stira [4]

Answer:

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<u>Step-by-step explanation:</u>

Given points end  Points are p(-3,-2) and q( 1,6)

<em>The distance of two points formula</em>

P Q = \sqrt{x_{2} - x_{1})^{2} + ((y_{2} -y_{1})^{2}   }

P Q = \sqrt{1 - (-3)^{2} + ((6 -(-2))^{2}   }

P Q = \sqrt{16+64} = \sqrt{80}

<em>The diameter 'd' = 2 r</em>

                       2 r = √80

                            = \sqrt{16 X 5}

                           = 4 \sqrt{5}

                     <em> r =  2√5</em>

<em>Mid-point of two end points </em>

<em>                        </em>(\frac{x_{1} + x_{2} }{2} , \frac{y_{1} +y_{2} }{2} ) = (\frac{-3+1}{2} ,\frac{-2 +6}{2} )<em></em>

<em>                                               = (-1 ,2)</em>

<em>Mid-point of two end points = center of the circle</em>

<em>                                     (h,k) = (-1 , 2)</em>

                 

The equation of the circle

           (x -h )² +(y-k)² = r²

<em>          (x -(-1) )² +(y-(2))² = (2(√5))²</em>

<em>         x² + 2 x + 1 + y² - 4 y + 4 = 20</em>

<em>          x² + 2 x + y² - 4 y  = 20 -5</em>

<em>           x² + 2 x + y² - 4 y  = 15</em>

<u><em>Final answer</em></u><em>:-</em>

<em>The equation of the circle   (x +1) )² +(y-(2))² = (2(√5))²</em>

<em>   or </em>

<em>The equation of the circle    x² + 2 x + y² - 4 y  = 15</em>

<em>                  </em>

6 0
3 years ago
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