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Mademuasel [1]
2 years ago
7

A guy wire runs from the top of a cell tower to a metal stake in the ground. Lincoln places a 10-foot tall pole to support the g

uy wire. After placing the pole, Lincoln measures the distance from the stake to the pole to be 5 ft. He then measures the distance from the pole to the tower to be 14 ft. Find the length of the guy wire, to the nearest foot.
Mathematics
1 answer:
Lisa [10]2 years ago
7 0

Step-by-step explanation:

2 right triangles are formed.

x is the angle btw wire and grnd

tan x = 10/5 = 2

tanx = ht of tower/(5+14)

2 = tower ht/19

tower ht = 38

length of wire =

\sqrt{ {38}^{2} +  {19}^{2}  }

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Flura [38]
Its B. 180 trust lol i got you
8 0
2 years ago
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Find the area of the triangle belowunits given are cm, cm^2, cm^3
zloy xaker [14]

Answer:

A_T=150cm^2

Explanation: We need to find the area of the triangle, We know that the area of any right triangle is:

A_T=\frac{1}{2}(b\times h)

Therefore in the information given we have the following:

\begin{gathered} h=20\operatorname{cm} \\ b=15\operatorname{cm} \end{gathered}

Therefore the Area of this triangle is as follows:

\begin{gathered} A_T=\frac{1}{2}(b\times h) \\ \therefore\rightarrow \\ A_T=\frac{1}{2}(20cm\times15cm)=\frac{1}{2}(20\times15)cm^2 \\ A_T=\frac{1}{2}(300)cm^2=150cm^2 \\ \therefore\rightarrow \\ A_T=150cm^2 \end{gathered}

Note! Units are centimeter-squared

4 0
1 year ago
The flagpole in front of VHS 50 feet tall. The angle of elevation from the end of its shadow to the top of the flagpole is 46°.
mamaluj [8]

Answer:

The length of the shadow is 48.28 feet.

Step-by-step explanation:

The flagpole at its shadow form a 46, 44, 90 triangle.

Let AB be the flagpole.  AC is the shadow.

Let's use the sine law to calculate AC.

\frac{AC}{sin(44)}=\frac{50}{sin(46)}\\AC=\sin(44)*\frac{50}{sin(46)}AC=48.28

5 0
3 years ago
I need help with this geometry question.
sashaice [31]

Answer:

Step-by-step explanation:

a). There are 8 points in the figure attached.

b). There are 9 lines in the given figure.

c). There are 5 planes in the figure attached.

d). Three collinear points are D,G and F.

e).  Four co-planar points are G, F, H and C.

f). Intersection of planes ABC and ABE is the common line AB.

g). Intersection of planes BCH and DEF is the common line EF.

h). Intersection of AD and DF is a point D.

3 0
3 years ago
I need help ☝️ urgent please hurry up man
muminat

Answer:

J) 110.88 mm^2

Step-by-step explanation:

height =6.93x2=13.86

Area=13.86x16x0.5=110.88

7 0
3 years ago
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