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Mademuasel [1]
3 years ago
7

A guy wire runs from the top of a cell tower to a metal stake in the ground. Lincoln places a 10-foot tall pole to support the g

uy wire. After placing the pole, Lincoln measures the distance from the stake to the pole to be 5 ft. He then measures the distance from the pole to the tower to be 14 ft. Find the length of the guy wire, to the nearest foot.
Mathematics
1 answer:
Lisa [10]3 years ago
7 0

Step-by-step explanation:

2 right triangles are formed.

x is the angle btw wire and grnd

tan x = 10/5 = 2

tanx = ht of tower/(5+14)

2 = tower ht/19

tower ht = 38

length of wire =

\sqrt{ {38}^{2} +  {19}^{2}  }

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Dear Sweet21574, the answer is D. Squre pyramid.
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Use the simple interest formula to find the ending balance
IgorC [24]
The answer would be 5,875.00
4 0
3 years ago
The cost of 7 chairs and 2 tables is equal.If the cost of 6 chairs and 5 tables is 10575, find the cost of 12 chairs.​
Igoryamba

Answer:

5400

Step-by-step explanation:

Let x represent the cost of a chair and y represent the cost of a table. We can use this to set up a system of equations:

7x=2y

6x+5y=10575

We can solve this system using substitution.

Start by rewriting the first equation in terms of x.

7x=2y\\\text{Divide both sides by 7}\\x=\frac{2}{7}y

Substitute this into the second equation:

6(\frac{2}{7}y)+5y=10575\\\frac{12}{7}y+5y+10575\\\frac{12}{7}y+\frac{35}{7}y=10575\\\frac{47}{7}y=10575

Multiply both sides by 7

47y=74025

Divide both sides by 47

y=1575

This means...

7x=2(1575)\\7x=3150

Divide both sides by 7

x=450

One chair costs 450. Now, multiply this number by 12 to find the cost of 12 chairs.

450*12=5400

12 chairs cost 5400.

7 0
3 years ago
Use the confidence interval to find the estimated margin of error. Then find the sample mean. A biologist reports a confidence i
mash [69]

Complete Question

A biologist reports a confidence interval of (3.5,4.9) when estimating the mean height (in centimeters) of a sample of seedlings. What is the estimated margin of error and the sample mean?

Answer:

The  margin of error is  E = 0.7

The  sample mean is  \=  x  =  4.2

Step-by-step explanation:

from the question we are told that

   The  upper limit is  k  =  4.9

    The  lower limit is  r = 3.5

Generally the margin of error is mathematically represented as

      E =  \frac{k - r}{ 2}

      E = \frac{ 4.9  -  3.5 }{2}

     E = 0.7

Generally the sample mean is mathematically evaluated as

        \=  x = k  -  E

=>    \= x  =  4.9 - 0.7

=>    \=  x  =  4.2

4 0
3 years ago
Charlie reads quickly. He reads 1\dfrac371 7 3 ​ 1, start fraction, 3, divided by, 7, end fraction pages every \dfrac23 3 2 ​ st
OLEGan [10]
<h2>Answer:</h2>

The number of pages he will read in one minute is:

        2\dfrac{1}{7}\ \text{pages}

<h2>Step-by-step explanation:</h2>

It is given that:

Charlie reads 1\dfrac{3}{7}\ \text{pages} in every \dfrac{2}{3}\ \text{minutes}.

We know that:

1\dfrac{3}{7}=\dfrac{10}{7}

This means that:

Charlie reads \dfrac{10}{7}\ \text{pages} in every \dfrac{2}{3}\ \text{minutes}.

This means that:

\text{In}\ \dfrac{2}{3}\ \text{minutes he reads}\ \dfrac{10}{7}\ \text{pages}\\\\\text{Hence}

\text{In}\ 1\ \text{minute he will read}\ \dfrac{\dfrac{10}{7}}{\dfrac{2}{3}}\ \text{pages}

\text{In}\ 1\ \text{minute he will read}\ \dfrac{10\times 3}{7\times 2}\ \text{pages}

Hence,

\text{In}\ 1\ \text{minute he will read}\ \dfrac{15}{7}\ \text{pages}

Hence,

\text{In}\ 1\ \text{minute he will read}\ \dfrac{15}{7}\ \text{pages}

\text{In}\ 1\ \text{minute he will read}\ 2\dfrac{1}{7}\ \text{pages}

4 0
3 years ago
Read 2 more answers
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