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3 years ago

Can you help me with 11 12 13 14 thank you so much

Mathematics

2 answers:

melamori03 [73]3 years ago

4 0

To find the mean, you add all of the numbers up and then divide by how many numbers there are. Mean is also known as the average. To find the medium, you have to list all the numbers in order then cross them out to find the middle. To find the mode, you find how many numbers are the same and count the number with the most repeats.
Ex for mean.) 5 + 2 + 5 = 15. 15/3 because there are 3 numbers in the equation. 15/3 = 5. The mean is 5.
Ex for median.) 1 2 2 3 4 5 7 9 9. 4 is in the middle so it is the median.
Ex for mode) 34 35 34 34 32 7. There are more 34s than any other number so 34 is your mode.

Diano4ka-milaya [45]3 years ago

4 0

The mean is the average. Add up all the numbers. Divide the sum by however many numbers there are. To find the median, list the numbers out from least to greatest. Take a number off the left, then a number of the right. Keep going until you have one number left in the middle. This is the median. If you have two numbers left, add them together and divide the sum by 2. The mode is the number that appears the most. If two or more numbers appear the same amount of times, they are all the mode. As for stem and leaf plots, you can Google them. They're really easy.

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What is the value of X?

VashaNatasha [74]

Answer:

considering the above 45*

to make the line that would represent 180*

180 - 45 = 135

(2 / 135 - 5)

62.5

62.5 is your answer

Step-by-step explanation:

3 0

3 years ago

On a coordinate plane, a curved line with a minimum value of (negative 1, negative 2), crosses the x-axis at (negative 2, 0) and

Oduvanchick [21]

Given:

A curved line with a minimum value of (-1,-2), crosses the x-axis at (-2, 0) and the y-axis at (0, 0).

To find:

x-intercepts of the function.

Solution:

The curved line passes through the points (-1,-2), (-2,0) and (0,0).

We know that, y-coordinate is zero at x-intercepts.

From the given points, only (-2,0) and (0,0) have 0 as y-coordinate.

So, x-intercepts of the function are (-2,0) and (0,0).

Therefore, the correct options are 1 and 3.

5 0

3 years ago

Read 2 more answers

Lines AB and CD (if shown) are straight lines. Find x.

lakkis [162]

Answer:

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7 0

3 years ago

What is the value of x in the equation 5(3x + 4) = 23?<br> A)43/15<br> B)3/15 <br> C)15/43<br> D)2/5

Romashka [77]

It would be B) 3/15
You distribute 5 to both 3x and 4, giving you 15x+20=23
Then, you subtract 20 from both sides of the equation, giving you 15x = 3
And then you divide both sides by 15 so you can isolate x

8 0

3 years ago

Can anyone help me do the questions that are circled with red and you don't need to do the graphing calculator thing, please

creativ13 [48]

Answer:

There are six problems circled in red.

As requested, only the analytical solutions are shown.

Question 16. Factor the polynomial

$44+15h+h^2$

Answer: (h + 4) (h + 11)

Question 17. Factor the polynomial

$40-22x+x^2$

Answer: (x - 2) (x -20)

Question 18. Factor the polynomial

$-24-10x+x^2$

Answer: (x - 12) (x + 2)

Question 19. Factor the polynomial

$-42-m+m^2$

Answer: (m - 7) (m + 6)

Question 20. Solve the equation

$x^2-7x+12=0$

Answer: x = 4 and x = 3

Question 22. Solve the equation

$x^2-6x=27$

Answer: x = 9 and x = - 3.

Explanation:

Question 16. Factor the polynomial

$44+15h+h^2$

1. Rearrange the terms:

$h^2+15h+44$

2. Open two parenthesis and place the common variable, h, as the first term of each.

$(h+a)(h+b)$

You are going to determine the values of a and b.

3. The values of a and b must satisfy that their product is 44 and their sum is 15.

a + b = 15 and a × b = 44

11 and 4 meet those conditions: 11 + 4 = 15, and 11 × 4 = 44.

So, the factored polynomial is:

$(h+4)(h+11)$

Question 17. Factor the polynomial

$40-22x+x^2$

1. Rearrange the terms:

$x^2-22x+40$

2. Write two binomials; each with first term x

(x-a)(x-b)

The negative sign for a comes from the negative sign before 22x; the negative sign of b comes from the product of the signs of -22x and + 40.

3. Find a and b such that a + b = 22 and a × b = 40

20 + 2 = 22 and 20 × 2 = 40, so the binomials are (x - 2) and (x - 20)

And the factored polynomial is:

$(x-2)(x-20)$

Question 18. Factor the polynomial

$-24-10x+x^2$

1. Rearrange the terms

$x^2-10x-24$

2. Sketch two binomials

$(x-a)(x+b)$

The negative sign for a corresponds to the negative sign for -10x, and the positive sign for b corresponds to the multplication of the signs of -10x and -4.

3. Find a and b such that their product is -24 and their aum is - 10.

Those numbers are - 12 and + 2:

- 12 + 2 = - 10
- 12 × (2) = - 24

Thus, the two factors are (x - 12) and (x +2).

And the factored polynomial is:

$(x-12)(x+2)$

Question 19. Factor the polynomial

$-42-m+m^2$

1. Rearrange the terms

$m^2-m-42$

2. Sketch the factors:

$(m-a)(m+b)$

The negative sign for a corresponds to the negative sign in front of m, the positive sign for b corresponds to the product of the signs of -m and -42.

3. Find two numbers, a and b, such that - a + b = - 1, and a × b = - 42

Those numbers are 6 and 7:

- 7 + 6 = - 1
-7 × 6 = - 42

Then, the factors are m - 7 and m + 6.

The factored polynomial is:

$(m-7)(m+6)$

Question 20. Solve the equation

$x^2-7x+12=0$

1. Factor the left side:

Find two numbers that sum -7 and their product is + 12. Those two numbers are - 4 and - 3.

$(x-4)(x-3)=0$

2. Use the zero product rule

x - 4 = 0 or x - 3 = 0

x = 4 or x = 3

Both, x = 4 and x = 3 are solutions.

Hence, the solutions are x = 4 and x = 3.

Question 22. Solve the equation

$x^2-6x=27$

1. Move 27 to the left side (using subtraction property of equalities):

$x^2-6x-27=0$

2. Factor the polynomial.

Find two numbers whose sum is - 6 and their product is - 27.

Those numbers are - 9 and + 3:

- 9 + 3 = - 6
- 9 × 3 = 27

$(x-9)(x+3)=0$

3. Zero product rule

$x-9=0\\ \\ x=9\\ \\ x+3=0\\ \\ x=-3$

The two solutions are: x = 9 and x = -3

3 0

4 years ago