Answer:
1348 light years.
Step-by-step explanation:
Please find the attachment.
Let x represent the distance between KA-7 and KA-11.
We have been given that the first system, KA-7, is 1200 light years away while the second system, KA-11, is 1700 light years away. Lucy sees an angle of 52 degrees between KA-7 and KA-11.
We can see from our attachment that Lucy, KA-7 and KA-11 forms a triangle and we will use law of cosines to solve for x.
Upon substituting our given values in above formula we will get,



Let us take square root of both sides of our equation.


Therefore, KA-7 and KA-11 are approximately 1348 light years apart.
Answer:
The constant m=-4, and b=33
Step-by-step explanation:
F(x)= MX+b
If f(6)=9 then x=6, m= -4
9= -4(6) + b
9= -24 + b
b= 9 + 24
b= 33
Therefore the constant m, which is the slope is -4 and b which is the intercept is 33
The y-in is -6
The x- in is -1 and -6
The vertex is (-3.5,-6.25)
The axis is -3.5
3/10 of the time = time spent on practicing warm up routines...
Time spent = 15 hours
remember that 'of' is usually multiply (x)
so ---- 3/10 x 15 =4.5 hrs
Hope this helps