6/4 or 1 and 2/4 thats a pretty easy question
Let A(4,12) and B(6,18)
RATE OF CHANGE = m = (y₂ - y₁) / (x₂ - x₁) = (18-12)/ (6-4)
m= 6/2 or m = 3
The linear equation in standard form is:
6x - 7y = -11
Which is the last option.
<h3>
How to get the equation of the line?</h3>
The line in slope-intercept form is written as:
y = a*x + b
We can see that the line passes through the points (-3, -1) and (1/2, 2), then the slope is:

Then we can write:
y = (6/7)*x + b
To find the value of b, we use the first point. It means that when x = -3, the value of y is -1, then we get:
-1 = (6/7)*-3 + b
-1 + 18/7 = b
-7/7 + 18/7 = b
11/7 = b
Then the equation is:
y = (6/7)*x + 11/7
If we multiply both sides by 7 we get:
7y = 6x + 11
Now we move the term with "x" to the left:
7y - 6x = 11
That is the line in standard form.
If we multiply both sides by -1, we get the last option:
6x - 7y = -11
If you want to learn more about linear equations:
brainly.com/question/1884491
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Answer:
144
Step-by-step explanation:
The sequence is:
0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987, 1597, 2584, 4181, 6765, 10946
so you can see the first term larger than 120 is the 144.
identity used is
x³ + y³+ z³– 3xyz = (x + y + z) (x² + y² + z² – xy – yz – zx).
then use
(x+y+z)² = x²+y²+z²+2(xy+yz+xz)
225= 83 + 2(xy+yz+xz)
xy+yz+xz = (225-83)/2
xy+yz+xz= 142/2
xy+yz+xz= 71
ok
now use identity
x³ + y³+ z³– 3xyz = (x + y + z) (x² + y² + z² – xy – yz – zx).
now
x³ + y³+ z³– 3xyz = 15 (83 – xy – yz – zx).
= 15[83 - (71)]
= 15×12
=180