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3 years ago

Y=-4x-41 that passes through (-2,7)

Mathematics

2 answers:

dalvyx [7]3 years ago

4 0

Answer:

Parallel: y=-4x-1

Perpendicular: y=-4x+13/2

Step-by-step explanation:

For the equation y=-4x-41, the slope is -4. Writing a line related to this equation has two options:

If the line will be parallel to it then this is the slope of the new line as well. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form.

(y-7)=-4(x--2)

y-7=-4x-8

y=-4x-1

If the line will be perpendicular to it then the slope is the negative reciprocal of the previous slope. It is 1/4.

(y-7)=1/4(x--2)

y-7=1/4x-1/2

y=-4x+13/2

olya-2409 [2.1K]3 years ago

4 0

Hello there,

Answer: y=-4x+13/2

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Given that g(x)=3x²-5x+7 find the following: g(-x)

AURORKA [14]

G(x) = 3x² - 5x + 7
g(-x) = -(3x² - 5x + 7)
g(-x) = -3x² + 5x - 7

This equation cannot be solved because of a few reasons,

1. This equation didn't show that it equals to 0.
2. Even if it equals to zero, square root of a negative number cannot be solved.
(I will show you what I mean)

-3x² + 5x - 7
is the same as
3x² - 5x + 7
by shifting the equation,

for example,
1 - 3 = -2
shifting other side
2 = -1 + 3

using 3x² - 5x + 7 to solve,

$Solve\ using\ the\ formular\ \ \boxed{ x= { \frac{-b \pm \sqrt{b^2-4ac} }{2a} } }$
a = 3
b = -5
c = 7
$x= { \frac {-(-5) \pm \sqrt{ (-5)^2-4(3)(7) } }{2(3)} }$
$x= { \frac {5 \pm \sqrt{-59} }{6} }$

∴This equation cannot be solved.

5 0

3 years ago

P(x < 21 | μ = 23 and σ = 3) enter the probability of fewer than 21 outcomes if the mean is 23 and the standard deviation is

Shkiper50 [21]

Answer:

(a) The value of P (X < 21 | μ = 23 and σ = 3) is 0.2514.

(b) The value of P (X ≥ 66 | μ = 50 and σ = 9) is 0.0427.

(d) The value of P (17 < X < 24 | μ = 21 and σ = 3) is 0.7495.

(e) The value of P (X ≥ 95 | μ = 80 and σ = 1.82) is 0.

Step-by-step explanation:

The random variable X is Normally distributed.

(a)

The mean and standard deviation are:

$\mu=23\\\sigma=3$

Compute the value of P (X < 21) as follows:

$P(X$

$=P(Z$

Thus, the value of P (X < 21 | μ = 23 and σ = 3) is 0.2514.

(b)

The mean and standard deviation are:

$\mu=50\\\sigma=9$

Compute the value of P (X ≥ 66) as follows:

Use continuity correction.

P (X ≥ 66) = P (X > 66 - 0.5)

= P (X > 65.5)

$=P(\frac{X-\mu}{\sigma}>\frac{65.5-50}{9})$

$=P(Z>1.72)\\=1-P(Z$

Thus, the value of P (X ≥ 66 | μ = 50 and σ = 9) is 0.0427.

(c)

The mean and standard deviation are:

$\mu=50\\\sigma=5$

Compute the value of P (X > 47) as follows:

$P(X>47)=P(\frac{X-\mu}{\sigma}>\frac{47-50}{5})$

$=P(Z>-0.60)\\=P(Z$

Thus, the value of P (X > 47 | μ = 50 and σ = 5) is 0.7258.

(d)

The mean and standard deviation are:

$\mu=21\\\sigma=3$

Compute the value of P (17 < X < 24) as follows:

$P(17$

$=P(-1.33$

Thus, the value of P (17 < X < 24 | μ = 21 and σ = 3) is 0.7495.

(e)

The mean and standard deviation are:

$\mu=80\\\sigma=1.82$

Compute the value of P (X ≥ 95) as follows:

Use continuity correction:

P (X ≥ 95) = P (X > 95 - 0.5)

= P (X > 94.5)

$=P(\frac{X-\mu}{\sigma}>\frac{94.5-80}{1.82})$

$=P(Z>7.97)\\=1-P(Z$

Thus, the value of P (X ≥ 95 | μ = 80 and σ = 1.82) is 0.

8 0

3 years ago

Help please! include how you did it and i will give you brainilist.

mihalych1998 [28]

Answer: A' (3, 6)

Step-by-step explanation: It is given that the point at is at the coordinate of (1, 2). In this coordinate, 1 represents the x-coordinate while 2 represents the y-coordinate. All you have to do is plug the values of x and y into (x+2)(y+4); so, it will look like this, (1+2)(2+4). Therefore, the new x-coordinate is 3 and the new y-coordinate is 6, so A'(3, 6).

5 0

3 years ago

PLEASE HELP!!!!!! IMA DESPRATE!!!!!!Determine whether f(x) = 2x3 − 6 is linear. If so, give the slope and y-intercept.

aleksklad [387]

The slope of the cubic polynomial and it's y-intercept are respectively; f(1) = -4 and f(0) = -6

<h3>What is the slope of the equation?</h3>

We are given the equation;

f(x) = 2x³ - 6

Now, because the highest power of x is 3, it means that this is a cubic polynomial and not linear because it has a degree of 3

Thus, let us differentiate to get the slope;

f'(x) = 6x² - 6

At f'(x) = 0; x = 1

Thus, slope is;

f(1) = 2(1)³ - 6

f(1) = -4

y-intercept is f(x) at x = 0. Thus;

f(0) = 2(0³) - 6

f(0) = -6

Read more about slope of equation at; brainly.com/question/1884491

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3 0

3 years ago

Birth weights at a local hospital have a Normal distribution with a mean of 110 oz and a standard deviation of 15 oz. The propor

OLga [1]

Answer:

The proportion of infants with birth weights between 125 oz and 140 oz is 0.1359 = 13.59%.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

$\mu = 110, \sigma = 0.15$