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3 years ago

Y=-4x-41 that passes through (-2,7)

Mathematics

2 answers:

dalvyx [7]3 years ago

4 0

Answer:

Parallel: y=-4x-1

Perpendicular: y=-4x+13/2

Step-by-step explanation:

For the equation y=-4x-41, the slope is -4. Writing a line related to this equation has two options:

If the line will be parallel to it then this is the slope of the new line as well. Use the point-slope form to write the equation, then simplify and convert into the slope intercept form.

(y-7)=-4(x--2)

y-7=-4x-8

y=-4x-1

If the line will be perpendicular to it then the slope is the negative reciprocal of the previous slope. It is 1/4.

(y-7)=1/4(x--2)

y-7=1/4x-1/2

y=-4x+13/2

olya-2409 [2.1K]3 years ago

4 0

Hello there,

Answer: y=-4x+13/2

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Graph the equation y= x^2 - 2x - 8 on the accompanying set of axes. You must plot 5 points including the roots and the vertex.

Vanyuwa [196]

Answer:

I'm not so sure about this one so sorry if this is wrong

Step-by-step explanation:

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3 years ago

8.35x - 1.5 = 71.98<br> (a) 8.6<br> (b) 8.8<br> (c) 9<br> (d) 10.3

prisoha [69]

<h3> Hola! :D ¡te invito a recibir ayuda de un latinoamericano puto!</h3><h2><u> _____________________________________ </u></h2><h2> 8.35x - 1.5 = 71.98</h2><h2> - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -</h2>

<u>El -1,5 qlero pasaría al otro lado positivo</u>

<u>Ahora, se suma 71.98 + 1.5 = 73,48</u>

<u>El 8.35 qlero que está multiplicando, pasa al otro lado pero dividiendo</u>

<u>Dividimos</u>

<h3> x = 8,8</h3><h2> - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -</h2><h2> <u>(b) 8,8</u> es la opción correcta</h2>

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2 years ago

A. Convert 39/7 to a mixed number

saul85 [17]

The answer to this question is A). 39 b). 56

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3 years ago

What is the difference between a factor of a number and a multiple of a number? use the number 25 has an example

Ne4ueva [31]

Answer:

factor: a submultiple; an integer value that gives an integer quotient when the number is divided by it.
multiple: the product of the number and another integer

Step-by-step explanation:

<h3>Factors</h3>

A set of factors of a number (N) is a set of integers {f1, f2, f3, ...} whose product is the number:

f1 × f2 × f3 × ... = N

Often the term "factors" is used to mean "prime factors," the set of prime numbers whose product is N.

When N = 25, the prime factors are {5, 5}. That is ...

5×5 = 25

<h3>Divisors</h3>

A "divisor" of a number is a sub-multiple of N. That is, the quotient N/k is an integer for some divisor k of N. Usually, we're interested in integer divisors. All prime factors will be integer divisors of N. The term "factor" is often used when the term "divisor" is meant.

Divisors of N = 25 include 1, 5, and 25. There will be an odd number of integer divisors (as here) if the number N is a perfect square.

<h3>Multiples</h3>

For an integer k, the value k×N is called a <em>multiple</em> of N, often, the <em>k-th multiple</em> of N.

Multiples of 25 include 25, 50, 75, 100, 125, and any other decimal number ending in 25, 50, 75, or 00.

<em>Another example</em>

When N=30, the prime factors are {2, 3, 5}. The divisors are {1, 2, 3, 5, 6, 10, 15, 30}. (Note there are an even number of divisors.) Multiples of 30 include 30, 60, 90, 120, ....

6 0

2 years ago

consider the quadratic form q(x,y,z)=11x^2-16xy-y^2+8xz-4yz-4z^2. Find an orthogonal change of variable that eliminates the cros

Bezzdna [24]

Answer:

$q(x,y,z)=16x^{2}-5y^{2}-5z^{2}$

Step-by-step explanation:

The given quadratic form is of the form

$q(x,y,z)=ax^2+by^2+dxy+exz+fyz$ .

Where $a=11,b=-1,c=-4,d=-16,e=8,f=-4$ .Every quadratic form of this kind can be written as

$q(x,y,z)={\bf x}^{T}A{\bf x}=ax^2+by^2+cz^2+dxy+exz+fyz=\left(\begin{array}{ccc}x&y&z\end{array}\right) \left(\begin{array}{ccc}a&\frac{1}{2} d&\frac{1}{2} e\\\frac{1}{2} d&b&\frac{1}{2} f\\\frac{1}{2} e&\frac{1}{2} f&c\end{array}\right) \left(\begin{array}{c}x&y&z\end{array}\right)$

Observe that $A$ is a symmetric matrix. So $A$ is orthogonally diagonalizable, that is to say, $D=Q^{T}AQ$ where $Q$ is an orthogonal matrix and $D$ is a diagonal matrix.

In our case we have:

$A=\left(\begin{array}{ccc}11&(\frac{1}{2})(-16) &(\frac{1}{2}) (8)\\(\frac{1}{2}) (-16)&(-1)&(\frac{1}{2}) (-4)\\(\frac{1}{2}) (8)&(\frac{1}{2}) (-4)&(-4)\end{array}\right)=\left(\begin{array}{ccc}11&-8 &4\\-8&-1&-2\\4&-2&-4\end{array}\right)$

The eigenvalues of $A$ are $\lambda_{1}=16,\lambda_{2}=-5,\lambda_{3}=-5$ .

Every symmetric matriz is orthogonally diagonalizable. Applying the process of diagonalization by an orthogonal matrix we have that:

$Q=\left(\begin{array}{ccc}\frac{4}{\sqrt{21}}&-\frac{1}{\sqrt{17}}&\frac{8}{\sqrt{357}}\\\frac{-2}{\sqrt{21}}&0&\sqrt{\frac{17}{21}}\\\frac{1}{\sqrt{21}}&\frac{4}{\sqrt{17}}&\frac{2}{\sqrt{357}}\end{array}\right)$

$D=\left(\begin{array}{ccc}16&0&0\\0&-5&0\\0&0&-5\end{array}\right)$

Now, we have to do the change of variables ${\bf x}=Q{\bf y}$ to obtain

$q({\bf x})={\bf x}^{T}A{\bf x}=(Q{\bf y})^{T}AQ{\bf y}={\bf y}^{T}Q^{T}AQ{\bf y}={\bf y}^{T}D{\bf y}=\lambda_{1}y_{1}^{2}+\lambda_{2}y_{2}^{2}+\lambda_{3}y_{3}^{2}=16y_{1}^{2}-5y_{2}^{2}-5y_{3}^2$

Which can be written as:

$q(x,y,z)=16x^{2}-5y^{2}-5z^{2}$

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3 years ago