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4 years ago

Simplify 252 over 288

1 answer:

8 0

So,

We have to prime factor the fraction.
$\frac{252}{288} --\ \textgreater \ \frac{2*2*3*3*7}{2*2*2*2*2*3*3}$

Cross out ones.
$\frac{7}{2*2*2}$

Multiply it out.
$\frac{7}{8}$

The fraction is now simplified.

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Find the Median of the data set: *<br>13, 15, 22, 9, 16, 19, 19

enot [183]

Step-by-step explanation: 16

the median is also the number that is halfway into the set so you put the numbers in order of smallest to biggest and find the one in the middle

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3 years ago

How do you find out if a ratio is equivalent

Keith_Richards [23]

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4 years ago

A manufacturer of pharmaceutical products analyzes specimens from each batch of a product to verify the concentration of the act

Alisiya [41]

Answer:

$0.82-2.977\frac{0.048}{\sqrt{15}}=0.783$

$0.82+2.977\frac{0.048}{\sqrt{15}}=0.857$

So on this case the 99% confidence interval would be given by (0.783;0.857)

So then we can conclude that at 99% of confidence the true mean is between (0.783;0.857) and the specification is satisfied since the value of 0.8 is on the confidence interval

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X= 0.82$ represent the sample mean

$\mu$ population mean (variable of interest)

s=0.048 represent the sample standard deviation

n=15 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=15-1=14$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,14)".And we see that $t_{\alpha/2}=2.977$

Now we have everything in order to replace into formula (1):

$0.82-2.977\frac{0.048}{\sqrt{15}}=0.783$

$0.82+2.977\frac{0.048}{\sqrt{15}}=0.857$

So on this case the 99% confidence interval would be given by (0.783;0.857)

So then we can conclude that at 99% of confidence the true mean is between (0.783;0.857) and the specification is satisfied since the value of 0.8 is on the confidence interval

5 0

3 years ago

A $120 wagon is on sale for 15 percent off. What is the sale price of the wagon?

melamori03 [73]

Answer:

Step-by-step explanation:

120*15%= 18 off

120-18= $102.00 new price

7 0

3 years ago

Read 2 more answers

How can I get the answer