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Anni [7]
3 years ago
10

In her calculations, Rosita will be using the square root of 2 often. She wants to use as few digits as possible, but at the sam

e time have sufficient precision. How should Rosita round the square root of 2 so that the approximation times 5 is greater than 7.05?
Mathematics
1 answer:
Sladkaya [172]3 years ago
6 0

Testing the multiplication for each case, it is found that she should round the square root of 2 to three decimal digits.

<h3>What is the square root of 2?</h3>

The square root of 2 is given by:

\sqrt{2} = 1.41421356237

With one decimal digit, the result of the multiplication is:

5 \times \sqrt{2} = 5 \times 1.4 = 7 < 7.05

With two decimal digits, the result of the multiplication is:

5 \times \sqrt{2} = 5 \times 1.41 = 7.05 = 7.05

With three decimal digits, the result of the multiplication is:

5 \times \sqrt{2} = 5 \times 1.414 = 7.07 > 7.05

Hence, she should round the square root of 2 to three decimal digits.

You can learn more about rounding at brainly.com/question/17248958

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Step-by-step explanation:

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As the sample size increases it comes closer to the population size, and so converge to a better result of researcher's analysis.

It means the size of the sample is proportional to the power of their statistical tests.

∴ As the size of the sample increases the power of statistical test increases.

Hence, If a research team increases the sample size for a study, the power of their statistical tests will <u>increases</u>.

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3 years ago
6 x 10^-2 is how many times a large as 2 x 10^-8?
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Answer:

the number 6\,\,\,10^{-2} is three million times larger than 2\,\,\,10^{-8}

Step-by-step explanation:

To answer this, just do the quotient of the first one over the second one, and use the rules for quotient of exponential expressions of the same base:

\frac{6\,\,\,10^{-2}}{2\,\,\,10^{-8}} =\frac{6}{2} \,\frac{10^{-2}}{10^{-8}} =3\,\,\,10^{-2+8}=3\,\,\,10^6=3000000

So the answer is: the number 6\,\,\,10^{-2} is three million times larger than 2\,\,\,10^{-8}

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