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Anni [7]
3 years ago
10

In her calculations, Rosita will be using the square root of 2 often. She wants to use as few digits as possible, but at the sam

e time have sufficient precision. How should Rosita round the square root of 2 so that the approximation times 5 is greater than 7.05?
Mathematics
1 answer:
Sladkaya [172]3 years ago
6 0

Testing the multiplication for each case, it is found that she should round the square root of 2 to three decimal digits.

<h3>What is the square root of 2?</h3>

The square root of 2 is given by:

\sqrt{2} = 1.41421356237

With one decimal digit, the result of the multiplication is:

5 \times \sqrt{2} = 5 \times 1.4 = 7 < 7.05

With two decimal digits, the result of the multiplication is:

5 \times \sqrt{2} = 5 \times 1.41 = 7.05 = 7.05

With three decimal digits, the result of the multiplication is:

5 \times \sqrt{2} = 5 \times 1.414 = 7.07 > 7.05

Hence, she should round the square root of 2 to three decimal digits.

You can learn more about rounding at brainly.com/question/17248958

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Odgmentis
Ugo [173]

Answer:

you got this kiddo

Step-by-step explanation:

4 0
3 years ago
Percent of discount is 25% and the sale price is 40$ what is the original amount?
Crank
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6 0
3 years ago
Rationalize the denominator and simplify. 5/4-√3
Yakvenalex [24]
I assume the denominator is (4-√3)
Multiple both top and bottom by (4+√3)
[5(4+√3)]/[(4-√3)(4+√3)]
=[20+5√3]/[4²-(√3)²]
=[20+5√3]/13
4 0
3 years ago
14. Solve for x.<br> 110<br> (8x - 1)<br> (5x + 36)<br> (6x - 2)<br> (7x+19)<br> 116<br> 110
marin [14]

Answer:

ummm i dont have enough information

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45
Lapatulllka [165]

The train will pass the jogger in 36 seconds.

Length of train = 120m

Speed of train = 45kmph

Distance by which the jogger is ahead of the engine of the train = 240 m

Speed of jogger = 9 kmph

To pass the jogger, the train will have to cover the length of the train and the distance by which the jogger is ahead of the engine of train.

Hence,

Distance = 120 + 240 = 360m

As,

Time = Distance/Speed

Relative speed of train w.r.t jogger = 45 - 9 = 36 kmph = 10 m/s

Hence,

Time = 360/10 = 36 seconds.

To learn more about train, here:-

brainly.com/question/21218609

#SPJ4

5 0
1 year ago
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