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1 year ago

These are the first four terms of a sequence. 3 -1 -5 -9. Find the nth term.

Mathematics

1 answer:

podryga [215]1 year ago

4 0

Answer:

4n-1

Step-by-step explanation:

Diffrence bweetween each number, 3 and -1, -1 and -5, -5 and -9 is 4

find the closest numbers

4*1=4

4*0=0

4*-1=-4

4*-2=-8

now we figure out how to make these numbers into our terms of this sequence

4n-1

4*1-1=3

4*0-1=-1

4*-1-1=-3

4*-2-1=-9

so the nth term is 4n-1

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Here are two closed containers and four balls just fit into each container. Each ball has a diameter of 60mm. Which container ha

Studentka2010 [4]

Answer:

Container B has smaller surface area.

Step-by-step explanation:

Given:

Container A

Radius = 60/2 = 30 mm

Height = 4 x 60 = 240 mm

Container B

Length = 120

Width = 120

Height = 60

Computation:

Surface area of container A (Cylinder) = 2πr[h+r]

Surface area of container A (Cylinder) = 2[22/7][60][120+60]

Surface area of container A (Cylinder) = 67,885.70 mm² (Approx)

Surface area of container B (Cuboid) = 2[lb+bh+hl]

Surface area of container B (Cuboid) = 2[(14,400)+(7,200)+(7,200)]

Surface area of container B (Cuboid) = 57,600 mm²

Container B has smaller surface area.

8 0

2 years ago

Explain why (cos((theta))? + (sin((theta))2 = 1

frez [133]

Imagine a right triangle where a and b are the legs and c is the hypothenuse.

Pitagora: a²+b²=c²

Divide by c

(a/c)²+(b/c)²=1

But a/c=sin(B) and b/c=cos(B)

Thus sin² + cos² = 1

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2 years ago

Please help me, what is m<4?

aniked [119]

Answer:

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4 0

2 years ago

find (a) the area and (b) the circumference of each circle using π=3.14. Round to the hundredths' place. 1. the diameter of the

Arada [10]

area = pi x r^2

circumference = 2x pi x r or pi x d

1st one diameter = 9.5 cm

so radius = 9.5/2 = 4.75

area = 3.14 x 4.75^2 = 70.85 square cm

circumference = 3.14 x 9.5 = 29.83 cm

2nd one radius = 4

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circumference = 2 x 3.14 x 4 = 25.12 cm

5 0

2 years ago

Read 2 more answers

2. In the circle shown, secants PE and PF have been drawn such that mCE  82 , mDF  98 and the ratio 3. In circle O, tangent

Andrew [12]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The arc PR is $\theta _{PR} = 84$

Step-by-step explanation:

A descriptive diagram of the diagram given in the question is shown on the first uploaded image

In the circle tangent $\= {M \= Q}$ , secant $PE$ and chord $PF$ are drawn

given that $\theta _ {MPQ} = 102^o$ , $\theta _{M} = 60^o$

The objective is to determine PR

From the diagram we see that MQ is a straight which implies that the the angle

$\theta_{NPM} = 180 -102$

$\theta_{NPM} = 78^o$

Now looking at triangle NMP we see that

$\theta _{MNP} = 180 -[ \theta_{NMP} + \theta _{NPM}]$

$\theta _{MNP} = 180 - [60 + 78 ]$

$\theta _{MNP} = 42 ^o$

Now the measure of an inscribed angle is half the measure of its arc intercepted, this statement is the inscribed angle theorem

So with the knowledge

Then

$\theta_{RNP} = \frac{1}{2} \theta_{PR}$

Looking at the diagram we see that

$\theta _{MNP} = \theta_{RNP} = 42 ^o$

$42 = \frac{1}{2} \theta _{PR}$

$\theta _{PR} = 2 * 42$

$\theta _{PR} = 84$

7 0

2 years ago

These are the first four terms of a sequence. 3 -1 -5 -9. Find the nth term.​

These are the first four terms of a sequence. 3 -1 -5 -9. Find the nth term.