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3 years ago

What are some similarities and differences between the Third Angle Theorem and the Triangle Angle-Sum Theorem?

Mathematics

1 answer:

Alborosie3 years ago

4 0

Answer:

The similarities are;

1) The Third Angle Theorem and the Triangle Angle-Sum Theorem are based on the sum of the angles in a triangle being equal to 180°

2) The Third Angle Theorem and the Triangle Angle-Sum Theorem are used to prove the measure of the third

3) The Third Angle Theorem and the Triangle Angle-Sum Theorem are triangle theorems

The differences are;

1) The Third Angle Theorem is mainly used to prove the similarity of two triangles, while Triangle Angle-Sum Theorem is used to find the measure of the third angle

2) The value of the third angle may not be determined when using the The Third Angle Theorem to prove the similarities between triangles while the value of the third angle is normally determined calculated when the Triangle Angle-Sum Theorem is used to find the third angle given the other two angles in the triangle

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

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3 years ago

For what values of the variables are the following expressions defined? 1. 5y+2 2. 18/y 3. 1/x+7 4. 2b/10−b Example: X>7

Serga [27]

Answer:

1. All real numbers

2. All real numbers except y = 0

3. All real numbers except x = -7

4. All real numbers except b = 10

Step-by-step explanation:

For any function to be defined at a particular value, it should not be approaching to a value $\infty$ or it should not give us the $\frac{0}{0}$ (zero by zero) form when the input is given to the function.

The value of function will depend on the denominator.

Now, let us consider the given functions one by one:

1. 5y+2

Here denominator is 1. So, it can not attain a value $\infty$ or $\frac{0}{0}$ (zero by zero) form

So, for all real numbers, the function is defined.

$2.\ \dfrac{18}{y}$

At y = 0, the value

$At\ y =0, \dfrac{18}{y} \rightarrow \infty$

So, the given function is defined for all real numbers except y = 0

$3.\ \dfrac{1}{x+7}$

Let us consider denominator:

x + 7 can be zero at a value x = -7

$At\ x =-7, \dfrac{1}{x+7} \rightarrow \infty$

So, the given function is defined for all real numbers except x = -7

$4.\ \dfrac{2b}{10-b}$

Let us consider denominator:

10-b can be zero at a value b = 10

$At\ b =10, \dfrac{2b}{10-b} \rightarrow \infty$

So, the given function is defined for all real numbers except b = 10

7 0

3 years ago

Anu

bija089 [108]

Answer:

Circumference of Circle B=19.625cm

Step-by-step explanation:

The circumference formula is: 2pie(r) = pie(d)

We have diameter of the first circle which is 6. Now, because the diameter of second circle is 25% greater than this,

Hence, we add 25% in 6:

6+25/100 =6+0.25=6.25 cm

Therefore, we have diameter of 6.25 for circle B.

Now, we need to find the circumference of the Circle A.

circumference= pie(d) = pie(6)= 3.14times6= 18.84

Now use the proportional reasoning to find Circumference of Circle B:

circumference of Circle A/diameter Circle A = circumference of Circle B/diameter Circle B

18.84/6=circumference of Circle B/6.25

Cross multiply and divide:

(18.84times6.25)/6 = Circumference of Circle B

Solve:

Circumference of Circle B=19.625cm

Hope this helps!

Mark brainliest if you think i helped! Would really appreciate!

7 0

3 years ago

Step by step please and thank you.

cupoosta [38]

Answer:

the probability is 2/9

Step-by-step explanation:

Assuming the coins are randomly selected, the probability of pulling a dime first is the number of dimes (4) divided by the total number of coins (10).

p(dime first) = 4/10 = 2/5

Then, having drawn a dime, there are 9 coins left, of which 5 are nickels. The probability of randomly choosing a nickel is 5/9.

The joint probability of these two events occurring sequentially is the product of their probabilities:

p(dime then nickel) = (2/5)×(5/9) = 2/9

_____

Alternate solution

You can go at this another way. You can list all the pairs of coins that can be drawn. There are 90 of them: 10 first coins and, for each of those, 9 coins that can be chosen second. Of these 90 possibilities, there are 4 dimes that can be chosen first, and 5 nickels that can be chosen second, for a total of 20 possible dime-nickel choices out of the 90 total possible outcomes.

p(dime/nickel) = 20/90 = 2/9

8 0

3 years ago