First of all we can draw a parallel line to divide the figure into a triangle and a rectangle as shown in the figure. To find the area of our rectangle, remember that the area of a rectangle is length times width, so
![A_{r} =lw](https://tex.z-dn.net/?f=A_%7Br%7D%20%3Dlw)
. Since we know for our figure that the length and width of our rectangle are 13cm and 6cm respectively, lets replace those values in our formula to get its area:
![A _{r} =(13cm)(6cm)](https://tex.z-dn.net/?f=A%20_%7Br%7D%20%3D%2813cm%29%286cm%29)
![A=78cm^{2}](https://tex.z-dn.net/?f=A%3D78cm%5E%7B2%7D%20)
Similarly, the area of a triangle is one half times base times height, so
![At=( \frac{1}{2})bh](https://tex.z-dn.net/?f=At%3D%28%20%5Cfrac%7B1%7D%7B2%7D%29bh%20)
. Since we know that our base is 8cm and our height 6cm, lets replace those values in our equation to find the area of our triangle:
![A_{t} =( \frac{1}{2})(8cm)(6cm)](https://tex.z-dn.net/?f=A_%7Bt%7D%20%3D%28%20%5Cfrac%7B1%7D%7B2%7D%29%288cm%29%286cm%29%20)
![A_{t} =24cm^{2}](https://tex.z-dn.net/?f=A_%7Bt%7D%20%3D24cm%5E%7B2%7D%20)
Now the only thing left is add our areas:
![A_{total} =78cm^{2}+24cm^{2} =102cm^{2}](https://tex.z-dn.net/?f=A_%7Btotal%7D%20%3D78cm%5E%7B2%7D%2B24cm%5E%7B2%7D%20%20%3D102cm%5E%7B2%7D%20)
We can conclude that the correct answer is <span>
A. 102</span>
Answer:
x=−5 and y=1
Step-by-step explanation:
Answer:
Please complete the question..
Step-by-step explanation:
You take 8% of 59.99 which is 4.80
then you add 4.80 to get 64.79.
Answer:
08-Oct-2009 — If a spherical balloon has a volume of 972 pi cubic centimeters, what is ... is 4.pi.r^2 (its area remember not volume) as 4/3.pi.r^3=972pi r=9 ... and it is good to know the squares of the next 10 numbers.