The area of the given square pyramid is:
total area = 1,100 inches squared.
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How to get the area of the pyramid?</h3>
On the second image, we can see that the pyramid is conformed of a square base and 3 triangles.
To get the surface area of the pyramid, we can just get the area of each of these simpler parts.
The base is a square of 22 in by 22 in, then the area of the base is:
B = (22in)*(22 in) = 484 in^2
For each triangle, the area will be:
A = (base side)*(height)/2
A = (22in)*(14in)/2 = 154 in^2
And we have 4 of these triangles, then the total area of the pyramid will be:
total area = B + 4*A = 484in^2 + 4*(154 in^2) = 1,100 in^2
If you want to learn more about square pyramids:
brainly.com/question/22744289
#SPJ1
Step-by-step explanation:
Iodine test for starch
Method:
Place one spatula of the food sample on a dish or 1 cm3 if the sample is liquid.
Using a dropper, place a few drops of iodine solution onto the food.
Record any change in the colour of the solution.
Starch is detected using iodine solution. This turns blue-black in the presence of starch.
A: 25.12 (26 if your rounding)
B: You have to multiply R by 2 then by pi (3.14)
C: 10.5 (11 if your rounding)
Step-by-step explanation:
For a: A circle's circumference is its diameter multiplied by pi (3.14) To get the diameter you would multiple the radius by 2. Therefore your answer being 25.12 (Round to 26 if you want)
For c: Divide 65 by pi then that answer by two.
1 75/1000
One and seven thousandth
Answer:
1.60 
Step-by-step explanation:
Assuming that this is a cylindrical pipe, the area can be determined by applying the formula for calculating the area of a circle.
i.e Area = 

So that,
for the inner part of the pipe,
r = 
= 
= 2.5 feet
Area of the inner part of the pipe = 

= 3.14 x 
= 19.625
Are of the inner part of the pipe is 19.63
.
Total diameter of the pipe = 5 + 0.2
= 5.2 feet
r = 
= 2.6 feet
Area of the pipe = 

= 3.14 x 
= 21.2264
Area of the pipe is 21.23
.
Thus the cross sectional area = Area of the pipe - Area of the inner part of the pipe
= 21.2264 - 19.625
= 1.6014
The cross sectional area of the cement pipe is 1.60
.