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3 years ago

8

Cameron is making bead necklaces he has 90 green brands and 108 blue beads . What is the greatest number of identical necklaces

he can make if he wants to use all of the beads

1 answer:

Keith_Richards [23]3 years ago

5 0

Forgot srry don't blame the girl

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Last one ok will give you branlist 7 grade math

Naya [18.7K]

Answer:

B

Step-by-step explanation:

hope this helps

6 0

3 years ago

Read 2 more answers

Solve the proportional equation 3/r = 5/r+3

romanna [79]

Answer:

r=9/2 or 4.5

Step-by-step explanation:

First of all our goal is to get R by itself

by cross multiplying we get,

(r+3)*3=5r

by distributive property we get

3r+9=5r

substracting 3r from both sides we get

9=2r

by dividing by 2 in both sides we get

r=9/2 or 4.5

6 0

3 years ago

Arrange the geometric series from least to greatest based on the value of their sums.

son4ous [18]

Answer:

80 < 93 < 121 < 127

Step-by-step explanation:

For a geometric series,

$\sum_{t=1}^{n}a(r)^{t-1}$

Formula to be used,

Sum of t terms of a geometric series = $\frac{a(r^t-1)}{r-1}$

Here t = number of terms

a = first term

r = common ratio

1). $\sum_{t=1}^{5}3(2)^{t-1}$

First term of this series 'a' = 3

Common ratio 'r' = 2

Number of terms 't' = 5

Therefore, sum of 5 terms of the series = $\frac{3(2^5-1)}{(2-1)}$

= 93

2). $\sum_{t=1}^{7}(2)^{t-1}$

First term 'a' = 1

Common ratio 'r' = 2

Number of terms 't' = 7

Sum of 7 terms of this series = $\frac{1(2^7-1)}{(2-1)}$

= 127

3). $\sum_{t=1}^{5}(3)^{t-1}$

First term 'a' = 1

Common ratio 'r' = 3

Number of terms 't' = 5

Therefore, sum of 5 terms = $\frac{1(3^5-1)}{3-1}$

= 121

4). $\sum_{t=1}^{4}2(3)^{t-1}$

First term 'a' = 2

Common ratio 'r' = 3

Number of terms 't' = 4

Therefore, sum of 4 terms of the series = $\frac{2(3^4-1)}{3-1}$

= 80

80 < 93 < 121 < 127 will be the answer.

4 0

2 years ago

Read 2 more answers

In a 24 km race, during which each runner maintains a constant speed throughout, Alice crosses the finish line while Becky is st

mr_godi [17]

Answer:6km

Step-by-step explanation:

Given

when Alice finishes the race Becky is 8km From finishing line

and caitlin 12 km from finishing line.

Suppose t is the time require by Alice to finish the race

and $V_a,V_b,V_c$ be the velocity of alice ,becky and caitlin

thus $t=\frac{24}{V_a}=\frac{24-8}{V_b}=\frac{24-12}{V_c}$

thus $\frac{V_b}{V_c}=\frac{4}{3}$

say t' is time required by beckey to complete 8 km thus

$V_b\times t'=8$

therefore for Caitlin

$V_c\times t'=\frac{8}{V_b}\times V_c=6$

Thus caitlin will cover a distance of 6 km in t' time and 6 km away from finishing.

7 0

3 years ago

456 students participate in and switch day the students raise money for charity so that the principle approve the day if you tur

alexandr402 [8]

Answer: The amount of money each student raised = $2

Step-by-step explanation:

Given : In charity

Total students participate= 456

Total collection = $912

Each student brought in the same amount of money , then the amount each student raised = $\dfrac{\text{Total collection }}{\text{Total students}}$

$=\$\dfrac{912}{456}\\\\=\$2$

Hence, the amount of money each student raised is $2.

3 0

3 years ago