Probaility is (desired outcomes)/(total possible outcomes)
odd numbers of dice is 3 (1,3,5)
desired outcomes =3
dice has 6 numbers
total possible outcomes of diece=6
3/6=1/2=dice
coin
tails=1
desired outcomes=1
total possibe=2 since 2 sides (head and tails)
cond poinbabiotiuyy=1/2
they are independend of each other since they do not influence each other
if they were like 'pick 2 collor balls and see what color you get, when you pick one, there is 1 less ball int he bucket so the propbabilit changes'
so
assuming that
P(M and N)= means
'the probability of M and N are both equal to "
The two events are independent. In the given scenario, P(M and N) =1/2.
Answer:
Step-by-step explanation:
Number of students participating in the competition = 13.
Total number of students in the school = 15.
Thus ,
the number of students who did not make to this competition =
Total number of students - number of students participated
= 15-13 = 2.
Now ,
probability of the student who do not makes it to the competition
= fraction of students who did not make to this competition from the total number of students .
=.
Statistical because you would need to know what cheetahs weigh. same goes for leopards though.
Answer:
a = 3, b = 3, c = 5 and d = 2.
Step-by-step explanation:
The prime factorization of 600 is 2^3 * 3 * 5^2
Yes because all sides would be equal to 5 which would give you 5*4 = 20 units.
