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Rudiy27
3 years ago
12

According to the 2000 U.S. Census Bureau, 49.65% of Texas residents were male. Consider the experiment of selecting ten Texans a

t random. If you are interested in determining the probabilities of selecting x males, is this a binomial probability distribution? And if so, what are the values of n, p, and q?
a. Yes; n = 0.4965, p =10, q = 0.5035
b. No
c. Yes; n = 0.5035, p = 10, q = 0.4965
d. Yes; n = 10, p = 0.4965, q = 0.503
Please explain why!!!!Have a nice day! :)
Mathematics
1 answer:
Ratling [72]3 years ago
6 0
This is the binomial probability distribution.
<span>n = 10 (</span>the number of randomly selected Texans)
<span>p = 0.4965 (t</span>he probability that randomly selected Texan will be male)
<span>q = 0.5035 (</span>the probability that randomly selected Texan will be female)
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8 0
3 years ago
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oksano4ka [1.4K]

Answer:

See Below.

Step-by-step explanation:

We have:

\displaystyle f(x)=(1-0.08)^{\frac{1}{12}(12t)}

First, we can subtract within the parentheses:

f(x)=(0.92)^{\frac{1}{12}(12t)}

By the properties of exponents:

f(x)=((0.92)^\frac{1}{12})^{12t}

Approximate. Use a calculator:

f(x)\approx (0.993)^{12t}

Notes:

0.993 is only an approximation, hence the approximately equal sign.

I'm not given the context of the problem, but it's simpler to just simplify in the exponent like so (the fractions cancel):

\displaystyle f(x)=(1-0.08)^{\frac{1}{12}(12t)}=(0.92)^t

Full Problem:

The value of Sara's car decreases at a rate of 8% per year.

We will use the exponential decay formula with a set time, given by:

f(x)=a(r)^{x/d}

Where a is the initial value, r is the rate, x is the time that has passed (dependent on d), and d is the amount of time for one decrease.

For this problem, we can ignore the initial value.

And since the value decreases at a rate of 8% per year, r = 0.92 (we acquire this from 1 - 0.08).

Part 1) Per Month:

Since it decreases per month, d = 12.

f(x)=(0.92)^{x/12}

Approximate:

f(x)=((0.92)^{1/12})^x\approx(.993)^x

In this case, x is measured in months.

Part 2) Per Week:

Since it decreases per week, d = 52.

f(x)=(0.92)^{x/52}

Approximate:

f(x)=((0.92)^1/52)^x\approx (.998)^x

In this case, x is measured in weeks.

Part 3) Per Day:

So, d = 365.

f(x)=(0.92)^{x/365}

Simplify:

f(x)=((0.92)^{1/365})^x\approx(.999)^x

In this case, x is measured in days.

Part 4)

So, as d increases, our r increases as well.

Therefore, the smaller the time interval (from months to weeks to days), the higher our rate of decrease is.

8 0
3 years ago
Help me pls with this complete a and B I will give you brainliest if answer is correct:-)​
Ganezh [65]

Answer:

a) Multiplied by 1.04

b)160(1.06)=169.6

Step-by-step explanation:

Its increasing so (1+4%) will be what it multiplied to.

Hope it helps u

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7 0
4 years ago
Solve the following equation. Then place the correct number in the box provided. 2(x + 1 ) - 3(x + 5) ≥ 0
7nadin3 [17]
When you divide by a negative make sure you switch the sign to the opposite side

4 0
3 years ago
Read 2 more answers
Find the solution of the system of equations.<br> 3x+4y=-7<br> -3x=8y=-1
Colt1911 [192]

Answer:

x = -5

y = 2

Step-by-step explanation:

3x + 4y = -7 -------eqn 1

-3x - 8y = -1 ------eqn 2

First, let's take eqn 1, to find the value of y

3x + 4y = -7

Make y the subject of the formula

4y = -7 - 3x

Divide both sides by 4, to get y

4y/4 = -7 - 3x / 4

y = (-7 - 3x) / 4

Substitute y into eqn 2

-3x - 8y = -1

-3x - 8(-7 - 3x) / 4 = -1

Open the bracket with -8

-3x + (56 + 24x )/ 4 = -1

LCM = 4

(-12x + 56 + 24x) / 4 = -1

(-12x + 24x + 56) / 4 = -1

(12x + 56)/4 = -1

Cross multiply

12x + 56 = -4

12x = -4 -56

12x = - 60

Divide both sides by 12 , the get the exact value of x.

12x/12 = -60/12

x = - 5

Insert the value of x = -5 into the equation 1

3x + 4y = -7

3(-5) + 4y = -7

-15 + 4y = -7

4y = -7 + 15

4y = 8

Divide both sides by 4

4y/ 4 = 8/4

y = 2

Hint, to confirm if the values are correct

Pick any of the two eqns

Let's pick eqn 2.

-3x - 8y = -7

x = -5

y = 2

-3(-5) - 8(2) =

= 15 - 16

= -1

So therefore, our values are correct

7 0
4 years ago
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